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Luba_88 [7]
3 years ago
12

Find LeShawn's average speed in meters per hour. 1,448 meters per minute

Mathematics
1 answer:
yanalaym [24]3 years ago
6 0
If he's average speed per minute is 1,448 meters per minute, and there are 60 minutes in a single hour. You would multiply 1,448 by 60 to get the answer of 86,880 meters per hour.
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Solve for the given time.
AlekseyPX

9514 1404 393

Answer:

  $319,525.64

Step-by-step explanation:

It appears you want the interest to accumulate for 15 years before you pay anything on the loan. The value of $180,000 appreciating at 3.9% annually will be ...

  $180,000·(1 +0.039)^15 = $319,525.64

If your lender allows you to wait 15 years before making any payment, your payment will be $319,525.64.

__

<em>Additional comment</em>

Home loans are usually paid with monthly payments computed from the formula ...

  A = P(r/12)/(1 -(1 +r/12)^(-12t))

where A is the monthly payment on principal P, r is the annual interest rate, t is the number of years.

For your $180,000 loan, the monthly payment is ...

  A = $180,000·(0.039/12)/(1 -(1 +0.039/12)^(-12·15)) ≈ $1322.44

The total of those payments is ...

  180·$1322.44 = $238,039.20

If you pay $1322.44 monthly on the loan, your total payment is $238,039.20.

3 0
3 years ago
O
jenyasd209 [6]

Answer:

thats not even understandable

4 0
1 year ago
on Wednesday jean's nursery received a shipment of 60 flowering crabapple trees. jean has ordered 80 trees. what percent of her
WITCHER [35]
75% when you have 60/80
7 0
3 years ago
The perimeter of a triangle is 56. The side lengths are x + 4, 3x + 7, and x + 9. What is the value of x?
Sidana [21]
<h3><u>Answer:</u></h3>
  • x = 7.2
<h3><u>Step-by-step explanation:</u></h3>
  • Perimeter: Side 1 + Side 2 + Side 3
  • => x + 4 + 3x + 7 + x + 9 = 56
  • => 5x + 20 = 56
  • => 5x = 56 - 20
  • => 5x = 36
  • => x = 7.2
<h3><u>Conclusion:</u></h3>

Therefore, the value of x is 7.2.

Hoped this helped.

BrainiacUser1357

5 0
2 years ago
How to find the average squared distance between the points of the unit disk and the point (1,1)
ddd [48]
The unit disk can be parameterized by the function

\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)

where 0\le r\le 1 and 0\le\theta\le2\pi. The squared distance between any point in this region (x,y)=(r\cos\theta,r\sin\theta) and the point (1, 1) is

(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2
=(r^2\cos^2\theta-2r\cos\theta+1)+(r^2\sin^2\theta-2r\sin\theta+1)
=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2
=r^2-2r(\cos\theta-\sin\theta)+2

The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

\dfrac{\displaystyle\iint_{x^2+y^2
=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}
=\dfrac{\frac{5\pi}2}\pi=\dfrac52
5 0
3 years ago
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