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Brilliant_brown [7]
3 years ago
13

1 consider the surface area of the pyramid shown (A) write the formula for the area of the base? What is the area of the base sh

ow your work (B) write the formula for the area of one side? What is the area of the side show your work (C) use part (a) and part (b) to find the total surface area. Show your work
Mathematics
1 answer:
Crank3 years ago
6 0
The answer is A. x+x+y+y= base, B. x or y would = one side, C. the total surface area is x*y.
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Maria had three less than twice as many points as Jane. Together they had 21 points. How many points did each girl have?
Mrrafil [7]
Maria had 13 points and jane had 8 points
8 0
3 years ago
To show me similarity to this statement, how can it be done?
Alenkasestr [34]

We start with the expression at the left of the equation.

We can combine the terms as:

\begin{gathered} \frac{2+\sqrt[]{3}}{\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}}}-\frac{2-\sqrt[]{3}}{\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}}} \\ \frac{2+\sqrt[]{3}}{\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}}}\cdot\frac{(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})}-\frac{2-\sqrt[]{3}}{\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}}}\cdot\frac{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})} \\ \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})-(2-\sqrt[]{3})\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})} \end{gathered}

We can now apply the distributive property for the both the numerator and denominator. We can see also that the denominator is the expansion of the difference of squares:

\begin{gathered} \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})-(2-\sqrt[]{3})\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2})^2-(\sqrt[]{2-\sqrt[]{3}}))^2} \\ \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})+(\sqrt[]{3}-2)\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{2^{}-(2-\sqrt[]{3})^{}} \\ \frac{\sqrt[]{2}\cdot(2+\sqrt[]{3})-\sqrt[]{2-\sqrt[]{3}}\cdot(2+\sqrt[]{3})+\sqrt[]{2}\cdot(\sqrt[]{3}-2)+\sqrt[]{2-\sqrt[]{3}}\cdot(\sqrt[]{3}-2)}{2-2+\sqrt[]{3}} \\ \frac{\sqrt[]{2}(2+\sqrt[]{3}+\sqrt[]{3}-2)+\sqrt[]{2-\sqrt[]{3}}(-2-\sqrt[]{3}+\sqrt[]{3}-2)}{\sqrt[]{3}} \\ \frac{\sqrt[]{2}(2\sqrt[]{3})+\sqrt[]{2-\sqrt[]{3}}(-4)}{\sqrt[]{3}} \\ 2\sqrt[]{2}-4\frac{\sqrt[]{2-\sqrt[]{3}}}{\sqrt[]{3}} \end{gathered}

We then can continue rearranging this as:

7 0
1 year ago
A point is randomly selected on the surface of a lake that has a maximum depth of 150 feet. Let y be the depth of the lake at th
Evgesh-ka [11]

Answer:

a) the possible values of y are all real numbers from 0 to 150.

b) y is a continous variable.

Step-by-step explanation:

If the maximum depth of the lake is 150 feet, in any point selected on the surface, the depth will be between 0 feet (takes this value of depth only at the shore) and 150 feet.

The depth is a physical measure that can be represented as a continous variable.

In that case, the possible values of y are all real numbers from 0 to 150.

4 0
3 years ago
Explain how to write x^2+5x+6 as the product of two linear factors. Use complete English and math sentences.
zepelin [54]

Answer:

(x + 3)(x + 2)

Step-by-step explanation:

Given

x² + 5x + 6

Consider the factors of the constant term (+ 6) which sum to give the coefficient of the x- term (+ 5)

The factors are + 3 and + 2 , since

3 × 2 = + 6 and + 3 + 2 = + 5 , then

x² + 5x + 6 = (x + 3)(x + 2) ← in factored form

7 0
3 years ago
What is the point-slope form of a line that has a slope of 3 and passes through point (1, 4)?
NeTakaya

Answer:

<em>(A). y - 4 = 3 ( x - 1 )</em>

Step-by-step explanation:

Slope "m" and ( x_{1} , y_{1} ) ⇒

Slope-point form of linear equation is y - y_{1} = m( x - x_{1} )

~~~~~~~~~~~~~

m = 3 and point with coordinates ( 1 , 4 )

<em>y - 4 = 3 ( x - 1 )</em>

6 0
2 years ago
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