All categories

2 years ago

PLEASEE HELP ME I DONT KNOW HOW TO DO THIS !!

Mathematics

1 answer:

larisa [96]2 years ago

8 0

G(h(0)) = 20

h(x) = x+4
h(0) = 0+4
h(0) = 4

g(x) = 5x
g(h(0)) = g(4) = 5(4) = 20

You might be interested in

Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

2 years ago

Surface Area Rectangular Prism

Goshia [24]

Surface area = 2(6*3) + 2(6*2) + 2*(2*3) = 36+24+12 = 72 cm^2

6 0

3 years ago

Read 2 more answers

Fill in the blanks to solve this equation (ANSWER QUICK)

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

$5+\frac{1}{2} (14b-8)=-6$

$5+7b-4=-6$

$7b+1=-6$

$-1$ $-1$

$7b=-7$

$/7$ $/7$

$b=-1$

Answers in order:

7 + 7b - 4 = -6

7b + 1 = -6

7b = -7

b = -1

Hope this helps!

3 0

2 years ago

~~HELP NEEDED NOW~~ ~~BE MY HERO!!~~

Natalka [10]

The population was 5,000 five hours ago!!

5 0

2 years ago

PLEASE HELP<br><br> Write the number in standard form.<br><br> (8 × 10) + (1 × 110) + (6 × 11,000)

mote1985 [20]

66,190 is the Answer if you add 80 to 110 and then add 190 to 66000

7 0

3 years ago