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3 years ago

8

Tim Worker wants to purchase an automobile warranty costing $856. If he chooses to make 12 equal payments, then in dollars and c

ents the average payment will be?

1 answer:

Svetlanka [38]3 years ago

3 0

Answer:

<u>$71.33</u>

Step-by-step explanation:

An automobile warranty costing = $856

It is required to make 12 equal payments

So, we need to divide $856 over 12

So, the average payment = 856/12 = $71.33

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Donna bought 5 bags of dog treats for 12.55. What is the cost per bag

Lera25 [3.4K]

Answer:

$2.51

Step-by-step explanation:

12.55/5= 2.51

a bag of dog treats is 2.51 per bag

4 0

2 years ago

Solve for x <br>x- 2x (12 - 1/2) =2 (4-2x) +20<br>A.-14/9<br>B.-9/14<br>C.14/9<br>D.9/14

MrMuchimi

Answer:

A

Step-by-step explanation:

-22x=-4x+28

-18x=28

x=-28/18=-14/9

7 0

2 years ago

Find the numerical value of the log expression. \log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3 loga=7logb=10logc=3 \log \

bija089 [108]

Answer:

32

Step-by-step explanation:

$\log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3\\\\ \log \dfrac{a^8c^2}{b^3}=8\log{a}+2\log{c}-3\log{b}=(8)(7)+(2)(3)-(3)(10)\\\\=56+6-30=\boxed{32}$

__

The applicable rules of logarithms are ...

log(ab/c) = log(a) +log(b) -log(c)

log(a^b) = b·log(a)

6 0

2 years ago

NEED HELP ASAP, I WILL GIVE YOU BRAINLIEST

tresset_1 [31]

Answer:

0.9412

Step-by-step explanation:

Ultimately, if you know the length of the arc, and you know the length of the radius, the central angle (in radians) is just how many radii long the arc is. angle=arc lengthradius length=16 feet17 feet≈0.9412.

8 0

2 years ago

Convert the polar coordinates (-3, -60°) to Cartesian coordinates.

notsponge [240]

Answer:

(1.5,-2.6)

Step-by-step explanation:

Given the polar coordinates (-3,60°).

Let our Cartesian coordinates be (x,y)

#We know that when converting the rectangular coordinates (x,y) to polar (r,θ), then:

$r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x$

#Using the illustration above, we can express our polar coordinates as:

$-3=\sqrt{x^2+y^2}\\\\-60\textdegree=tan^{-1}(y/x}$

#Solve simultaneously to solve for x and y:

$(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\ y \ in\ i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6$

Hence, the Cartesian coordinates are (1.5,-2.6)

6 0

2 years ago