If a1 is the first term of an arithmetic sequence and d is the common difference, then the formula for finding thenthtermofthesequenceisan =a1+(n−1)d. Wehavebeengivena1 =5andd=15. We’reaskedtofindn=40. an =a1 +(n−1)d a40 = 5+(40−1)·15 = 5+39·15 = 590 The 40th term of this sequence is 590.
He overdrew his account by $19, so he is at $-19. His bank charges $35 fee. -19 - 35 = -54. He deposits $60, so 60 + (-54) = 6. He has $6 as his ending balance.
