The correct answer is: [B]: "40 yd² " .
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First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
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→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
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Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
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Now, we add the areas of BOTH the triangle AND the square:
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→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
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Answer:
Part A: [0,2], Part B: [2, 4], Part C: [8,10], Part D: 0 ft
Step-by-step explanation:
Part A: The time between 0 seconds to 2 seconds is the time when it's increasing. There is no other time like that.
Part B: The graph shows a straight line so therefore it is staying the same.
Part C: The graph shows a sharp decline.
Part D: Starting from the 10th second, the balloon already hit to ground so it would only make sense for it to stay there...
F(C) = 9/5C + 32
I'll just change F(C) to y and 9/5C to 9/5x.
y = 9/5x + 32
inverse...
x = 9/5y + 32
9/5y = x - 32
y = 5/9x - 160/9
Sooooo
F(C) = 5/9C - 160/9
Answer:
(−2)(2)+(3)(−5)
=−19
Step-by-step explanation:
Hey!
Hope this helps...
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<em>Question 7:</em> Is the Graph a 1-to-1?
The answer is: No
<em>Reason: </em>If you look at the graph, you see that when the x value is -1 the y value is -2, when x is 0, y is 0. When x is 1, y is 2, when x is 3, y is 4, and so on and so on...
<em>Question 9:</em> What is f(2)?
The answer is: When f (or x) is 2, y is 3... so f(2) = 3
<em>Reason:</em> (Look at reason for Question 7)
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