Question

A company that offers tubing trips down a river rents tubes for a person to use for $20 and “cooler” tubes to carry food and water for $12.50. A group spends $270 to rent a total of 15 tubes. How many of each type of tube does the group rent?

Answer 1

The group rent 11 river rent tubes and 4 cooler tubes.

Step-by-step explanation:

Rent for river rent tube = $20

Rent for cooler tubes = $12.50

Total spent = $270

Total tubes rented = 15

Let,

x be the number of river rent tube.

y be the number of cooler tubes.

According to given statement;

x+y=15    Eqn 1

20x+12.50y=270    Eqn 2

Multiplying Eqn 1 by 20

$20(x+y=15)\\20x+20y=300\ \ \ Eqn\ 3$

Subtracting Eqn 2 from Eqn 3

$(20x+20y)-(20x+12.50y)=300-270\\20x+20y-20x-12.50y=30\\7.50y=30$

Dividing both sides by 7.5

$\frac{7.5y}{7.5}=\frac{30}{7.5}\\y=4$

Putting y=4 in Eqn 1

$x+4=15\\x=15-4\\x=11$

The group rent 11 river rent tubes and 4 cooler tubes.

Keywords: linear equations, subtraction

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