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Ymorist [56]
3 years ago
5

An airplane can ascend at a rate of 54 1/2 meters 2/3 of a second. how many meters can the airplane acend in one second

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0
The answer is 81.75. 54 1/2 divided by 2/3
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3 years ago
What is the area of the trapezoid?<br><br> Enter your answer in the box.
Oksi-84 [34.3K]

Answer:In Euclidean geometry, a convex quadrilateral with at least one pair of parallel sides is referred to as a trapezium in English outside North America, but as a trapezoid in American and Canadian English  

a+b 2h

Step-by-step explanation:

4 0
3 years ago
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Mark for review (Will be highlighted on the review page) 1. Solve this equation: 80 = 3y + 2y + 4 + 1.
saul85 [17]
First combine the like terms 3y + 2y to get 5y. Then combine 4 + 1 to get 5. Your equation will now be 80 = 5y + 5. To solve for y, 5 needs to be subtracted from both sides of the equation leaving 75 = 5y. Final step to solving for y, 5 needs to be divided from each side of the equation leaving the final answer of
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7 0
3 years ago
When placed end to end, three red rods are 2 cm longer than than 2 blue rods. Three blue rods are 2 cm longer than four red rods
Oxana [17]

Answer:

Red = 10 cm, blue = 14 cm

Step-by-step explanation:

<em>Let the length of each red rod be </em><em>r </em><em>and each blue rod be </em><em>b</em>

<u>Then we have:</u>

  • 3r - 2b = 2
  • 3b - 4r = 2

<u>Multiply the first equation by 3 and the second one by 2:</u>

  • 9r - 6b = 6
  • 6b - 8r = 4

<u>Add the equations to eliminate one of variables:</u>

  • 9r - 8r = 6 + 4
  • r = 10 cm

<u>Find the value of b:</u>

  • 3*10 -2b = 2
  • 30 - 2 = 2b
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  • b = 14 cm

5 0
3 years ago
Which of the following sets could be the sides of a right triangle?
coldgirl [10]

Answer: Choice B) {3, 5, sqrt(34)}

=====================================

Explanation:

We can only have a right triangle if and only if a^2+b^2 = c^2 is a true equation. The 'c' is the longest side, aka hypotenuse. The legs 'a' and 'b' can be in any order you want.

-----------

For choice A,

a = 2

b = 3

c = sqrt(10)

So,

a^2+b^2 = 2^2+3^2 = 4+9 = 13

but

c^2 = (sqrt(10))^2 = 10

which is not equal to 13 from above. Cross choice A off the list.

-----------

Checking choice B

a = 3

b = 5

c = sqrt(34)

Square each equation

a^2 = 3^2 = 9

b^2 = 5^2 = 25

c^2 = (sqrt(34))^2 = 34

We can see that

a^2+b^2 = 9+25 = 34

which is exactly equal to c^2 above. This confirms the answer.

-----------

Let's check choice C

a = 5, b = 8, c = 12

a^2 = 25, b^2 = 64, c^2 = 144

So,

a^2+b^2 = c^2

25+64 = 144

89 = 144

which is a false equation allowing us to cross choice C off the list.

7 0
3 years ago
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