4 years ago

An airplane can ascend at a rate of 54 1/2 meters 2/3 of a second. how many meters can the airplane acend in one second

Mathematics

1 answer:

RideAnS [48]4 years ago

4 0

The answer is 81.75. 54 1/2 divided by 2/3

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Let (8,−3) be a point on the terminal side of θ. Find the exact values of cosθ, cscθ, and tanθ.

denis23 [38]

Answer:

$\text{Cos}\theta=\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}$

$\text{Csc}\theta=-\frac{\sqrt{73}}{3}$

$\text{tan}\theta =\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}$

Step-by-step explanation:

From the picture attached,

(8, -3) is a point on the terminal side of angle θ.

Therefore, distance 'R' from the origin will be,

R = $\sqrt{x^{2}+y^{2}}$

R = $\sqrt{8^{2}+(-3)^2}$

= $\sqrt{64+9}$

= $\sqrt{73}$

Therefore, Cosθ = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}$

Sinθ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}=\frac{y}{R}=\frac{-3}{\sqrt{73} }$

tanθ = $\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}$

Cscθ = $\frac{1}{\text{Sin}\theta}=\frac{R}{y}=-\frac{\sqrt{73}}{3}$

6 0

4 years ago

Solve this system of equations.<br><br> x + y = -3<br><br> x - y = 1

Sindrei [870]

A. (-1,-2)

Because:
x + y = -3
-1 + (-2) = -3
-3 = -3

x - y = 1
-1 - (-2) = 1
-1 + 2 = 1
1 = 1

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I do believe you are right

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amm1812

Answer:

0.833

Step-by-step explanation:

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Ali’s dog weighs 8 times as much as her cat. Together, the two pets weigh 54 pounds. How much does Ali’s dog weigh?

baherus [9]

Ali's dog weighs 48 pounds.

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