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gregori [183]
3 years ago
7

9x – 5 < –41 or 3x + 13 > 7

Mathematics
2 answers:
aev [14]3 years ago
5 0
9x - 5 < -41
    +5      +5
9x < -36
x < -4

3x + 13 > 7
       -13   -13
3x      > -6
x > -2

x < -4 OR x >2
Elis [28]3 years ago
4 0
9x-5<-41                  or          3x+13>7
9x-5+5<-41+5                        3x+13-13>7-13 
9x/9<-36/9                             3x/3>-6 /3 
x<-4                                      x>-2
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This is an example of an arithmetic series: 6 + 8 + 10 + 12 + . . . + (4 + 2n) + . . .
nasty-shy [4]

True. A series is arithmetic if its terms come from an arithmetic sequence.

And a sequence is said to be arithmetic any of its two consecutive terms differ by a fixed difference, common to any consecutive pair.

As you can see, in this case, all terms differ by 2, so the sequence

6,\ 8,\ 10,\ 12,\ \ldots,\ 4+2n

is arithmetic, and thus the series

6 + 8 + 10 + 12 + \ldots + (4+2n)

is arithmetic as well.

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3 years ago
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3 years ago
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If a person puts 1 cent in a piggy bank on the first day, 2 cents on the second day, 3 cents on the third day, and so forth, how
cluponka [151]
This is an arithmetic sequence with the common difference being 1

and if u have 1 cent on day 1 and 2 cents on day 2....then on day 40, u would have 40 cents....but we need the sum of all the days..

the sum of an arithmetic sequence can be found using the formula :
sn = n(a1 + an) / 2
n = number of terms = 40
a1 = first term = 1
an = last term = 40

now we sub
s(40) = 40(1 + 40) / 2
s(40) = 40(41)/2
s(40) = 1640/2
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4 0
3 years ago
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