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liq [111]
3 years ago
13

I’m struggling I’m only in 6th grade sooo.....

Mathematics
1 answer:
sdas [7]3 years ago
8 0

Answer:

10. he charges $16 dollars

11. Alastair

Step-by-step explanation:

fyi if u have problem most times when u look up the assignment name itll give you the answer key.

Hope it helps

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An airline company has a 60% markup rate on its tickets. If the original cost of a ticket is $229, what is the amount of markup?
Evgesh-ka [11]

Answer:

$137.40

Step-by-step explanation:

The markup will be 0.60($229), or $137.40

5 0
3 years ago
A manufacturer of metal fasteners expects to ship an average of 1197.00 boxes of fasteners per day. A random sample of 24 days p
lana66690 [7]

Answer:

The p-value obtained is less than the significance level at which the test was performed, hence, we reject the null hypothesis, accept the alternative hypothesis & conclude that there is evidence showing that the average number of boxes shipped per day is different from 1197.00

Step-by-step explanation:

For hypothesis testing, we first clearly state our null and alternative hypothesis.

The null hypothesis is that there is no evidence showing that the average number of boxes shipped per day is different from 1197.00. That is, there is no significant difference between the number of boxes shipped per day and 1197.00

And the alternative hypothesis is that there is evidence showing that the average number of boxes shipped per day is different from 1197.00

Mathematically, the null hypothesis is

H₀: μ₀ = 1197.00

The alternative hypothesis is

Hₐ: μ₀ ≠ 1197.00

To do this test, we will use the t-distribution because no information on the population standard deviation is known

So, we compute the t-test statistic

t = (x - μ₀)/σₓ

x = sample mean = 1193.69 boxes per day

μ₀ = standard that we're comparing the sample mean with = 1197.00

σₓ = standard error of the sample mean

= (σ/√n)

where n = Sample size = 24 days

σ = standard deviation of the sample = 3.3166 boxes per day

σₓ = (3.3166/√24) = 0.677

t = (1193.69 - 1197) ÷ 0.677

t = -4.89

checking the tables for the p-value of this t-statistic

Degree of freedom = df = n - 1 = 24 - 1 = 23

Significance level = 0.05

p-value (for t = -4.89, at 0.05 significance level, with a two tailed condition) = 0.000061

The interpretation of p-values is that

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

So, for this question, significance level = 5% = 0.05

p-value = 0.000061

0.000061 < 0.05

Hence,

p-value < significance level

This means that we reject the null hypothesis, accept the alternative hypothesis & conclude that there is evidence showing that the average number of boxes shipped per day is different from 1197.00

Hope this Helps!!!

6 0
3 years ago
Pls help asap i will give branerlist plus 10 ponts
Luden [163]
4 and 5 are the only constant terms
8 0
3 years ago
Read 2 more answers
An equilateral triangle with side length 1 cm is shown in the diagram, work out the area of the triangle.
tatyana61 [14]

Answer:

1/2 cm

Step-by-step explanation:

3 0
3 years ago
Find the coordinates of the midpoint of CM with endpoints C(1, -6) and M(7,5).
Vilka [71]

Answer: The coordinates of the midpoint of CM with endpoints C(1, -6) and M(7,5) are (4,-\dfrac{1}{2}).

Step-by-step explanation:

We know that the coordinates of the midpoint(x,y) of line joining A(a,b) and B(c,d) is given by :-

(x,y)=(\dfrac{a+c}{2},\dfrac{b+d}{2})  .....(i)

Given : The coordinates of endpoints of CM are C(1, -6) and M(7,5)

Then , by using (i) , the coordinates of the midpoint of CM would be :-

(\dfrac{1+7}{2},\dfrac{-6+5}{2})\\\\=(\dfrac{8}{2},\dfrac{-1}{2})\\\\=(4,-\dfrac{1}{2})

Hence,  the coordinates of the midpoint of CM with endpoints C(1, -6) and M(7,5) are (4,-\dfrac{1}{2}).

3 0
3 years ago
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