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Basile [38]
2 years ago
7

Jose invested $5,100 in an account paying an interest rate of 8 % compounded

Mathematics
1 answer:
melisa1 [442]2 years ago
7 0

Answer:

I think he will have 6,56$

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Two similar triangles have have areas of 75 m2 and 12 m2. find the ratio of the perimeters
soldi70 [24.7K]

we know that having similar triangles so the ratio of sides,area and volume are same.

s/s=s^2/s^2

we know that s^2 will be the area of triangle.

s^2/s^2=75/12

so s/s=\sqrt{75/12}

so the ratio of the perimeter of two triangles will be

(s+s+s)/(s+s+s)=(\sqrt{75} +\sqrt{75} +\sqrt{75} )/(\sqrt{12}+\sqrt{12} +\sqrt{12} )

ratio of the perimeter=\sqrt{225} /\sqrt{36}

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3 years ago
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The figure below shows rectangle ABCD with diagonals segment AC and segment DB:
djverab [1.8K]

Answer:

segment BC ≅ segment BC (reflexive property of congruence)  

Step-by-step explanation:

Reflexive property of congruence states that an angle, line segment, or shape is always congruent to itself.

Before statement 6, you need to prove that side BC is the same for both triangles

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Valentin [98]

Answer:

x= 5 1/3

Step-by-step explanation:

l3x-5l=11

3x-5=11

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Can someone help me with a math test​
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sure

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whats it based on?

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Answer of a ²-10a+16-6b-b^2​
german

\quad a^2-10a+16-6b-b^2

$=(a^2-10a)-(b^2+6b) +16$

$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$

$=(a-5)^2-25-(b+3)^2+9+16$

$=(a-5)^2-(b+3)^2$

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3 years ago
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