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Ivahew [28]
3 years ago
8

Determine the relationship

Mathematics
1 answer:
Oksanka [162]3 years ago
7 0

Answer:

Perpendicular because the slopes are opposite reciprocals

Step-by-step explanation:

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Help Pls! It's for my Math 4! Scalar Multiplication!
prohojiy [21]

Answer:

Concept: Physics Qualitative Analysis.

  • Scalar values are constant and compared to vector values they do not have a direction or magnitude or a gradient representation.
  1. Lets get started by setting up the equation
  2. They want us to find 3U-2V
  3. Given U= <6,6> V=<6,-6>
  4. Now we plug in and solve!
  5. 3<6,6>- 2<6,-6>
  6. <18,18>-<12,-12>
  7. Subtract
  8. <18-12,18-(-12)>
  9. Hence that gives us a result of <6,30>
  10. Now with the skills you gained solve the rest!!!
8 0
3 years ago
Read 2 more answers
If anyone could help it would be greatly appreciated
Ira Lisetskai [31]

Answer:

Step-by-step explanation:

area of one triangle=(1/2)×6×4=12 m²

area of four triangles=4×12=48 m²

area of square=6×6=36 m²

total area=48+36=84 m²

4 0
4 years ago
Cindy took a multiple choice test. The ratio of number of problems Cindy got incorrect to the number of problems she got correct
Nezavi [6.7K]

Answer:

42

Step-by-step explanation:

Divide 14/2 *6 to get your ratio.

Hope this helps!

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4 0
3 years ago
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Marlin Davies buys a truck for $28,000. In three years, the truck depreciates 48% in value. How much is the truck worth in three
harkovskaia [24]

In three years the Marlin's truck is worth 13,440$

To find percentage of a number, multiple it with in 0. Of the number.

Example: 28,000 ×. 48

That equals 13,440

So 48% of 28,000 is 13,440

5 0
3 years ago
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Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join
zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx  = 1

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y)  and replacing a and b with their respective values, we have

\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx  = 1

Since c is a constant, we can bring it out of the integral sign; to give us

c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx  = 1

Open the bracket

c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx  = 1

Integrate with respect to y

c\int\limits^3_0 {\frac{xy^{2}}{2}  +\frac{xy^{3}}{3} } \, dx (0,3}) = 1

Substitute 0 and 3 for y

c\int\limits^3_0 {(\frac{x* 3^{2}}{2}  +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2}  +\frac{x * 0^{3}}{3})} \, dx = 1

c\int\limits^3_0 {(\frac{x* 9}{2}  +\frac{x * 27}{3} ) - (0  +0) \, dx = 1

c\int\limits^3_0 {(\frac{9x}{2}  +\frac{27x}{3} )  \, dx = 1

Add fraction

c\int\limits^3_0 {(\frac{27x + 54x}{6})  \, dx = 1

c\int\limits^3_0 {\frac{81x}{6}  \, dx = 1

Rewrite;

c\int\limits^3_0 (81x * \frac{1}{6})  \, dx = 1

The \frac{1}{6} is a constant, so it can be removed from the integral sign to give

c * \frac{1}{6}\int\limits^3_0 (81x )  \, dx = 1

\frac{c}{6}\int\limits^3_0 (81x )  \, dx = 1

Integrate with respect to x

\frac{c}{6} *  \frac{81x^{2}}{2}   (0,3)  = 1

Substitute 0 and 3 for x

\frac{c}{6} *  \frac{81 * 3^{2} - 81 * 0^{2}}{2}    = 1

\frac{c}{6} *  \frac{81 * 9 - 0}{2}    = 1

\frac{c}{6} *  \frac{729}{2}    = 1

\frac{729c}{12}    = 1

Multiply both sides by \frac{12}{729}

c    =  \frac{12}{729}

c    =  0.0165 (Approximately)

8 0
3 years ago
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