H,t,h,h they are both equal portability because you could get eithed
No, because if you substitute (4, -2) into x and y in each equation, they are not the same as the value on the right side of the equation.
2(4) + 4(-2) = - 2
8 + -8 = -2
0 = -2 <---- this is not correct.
-4(4) + -2 = -14
-16 + -2 = -14
-18 = -14 <----- this is not correct.
Answer:
this i not high school work
Answer:
x = 19
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
(x-7+4) * 4 = 8^2
(x-3)*4 = 64
Divide each side by 4
x-3 =16
Add 3 to each side
x-3+3 = 16+3
x = 19
Change the x and y
Then solve for y
X= 8y+1
Subtract 1 from both sides
X-1=8y
Divide by 8
X-1 /8 = y
