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astraxan [27]
4 years ago
8

Find the direct relationship between y and x . x=e^2t y=e^t

Mathematics
2 answers:
nekit [7.7K]4 years ago
8 0

Answer:

Step-by-step explanation:

x=e^2t

y=e^t

you. have : x=e^2t  =(e^t)² = y²

the direct relationship between y and x is : x = y²

olya-2409 [2.1K]4 years ago
5 0

Answer:

x = y²

Step-by-step explanation:

Given

x = e^{2t} and y = e^{t}

Note that

x = e^{2t} = e^{t} × e^{t} = y²

Thus x = y²

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Write the slope-intercept form of the equation of each line. 9x-7y=-7
makkiz [27]
Slope intercept form is y = mx + b.....so lets solve for y

9x - 7y = -7 .....subtract 9x from both sides
-7y = -9x - 7...now we divide both sides by -7
y = 9/7x + 1 <==
6 0
3 years ago
Which of the following are solutions to this equation 3n+4=24-n a) n=1 b) n=3 c) n=5 d) n=7​
g100num [7]

Answer:

The correct option is c) n=5.

Therefore the solution to

3n+4=24-n

is

n=5

Step-by-step explanation:

Given:

3n+4=24-n

To Find;

n = ?

Solution:

3n+4=24-n      ........Given

Add + n to both the side

3n+4+ n=24-n+n\\4n+4=24

Now Subtract 4 on both the side

4n+4-4=24-4\\4n=20

Dividing by 4 on both side

\dfrac{4n}{4}=\dfrac{20}{4}\\\\n=5

Therefore the solution to

3n+4=24-n

is

n=5

4 0
3 years ago
Help plsss
LenKa [72]
<h3></h3><h2>⭐ Development:</h2><h3></h3>

  • Having the expression, let's modify it so it becomes a 2nd degree equation:

\large {\text {$ \sf \cfrac{1}{2x^2} -2 = 0 $}}

  • Now, we will multiply per 2x² both sides of equation...

\large {\text {$ \sf \cfrac{1}{2x^2}\cdot \:2x^2-2\cdot \:2x^2=0\cdot \:2x^2 $}

                 \searrow

                     \large {\text {$ \sf 1-4x^2=0$}}

  • We have to write in standard form...

\large {\text {$ \sf -4x^2+1 = 0 $}}

<u>                                                                                                      </u>

<u />

\large {\text{$\sf x=\cfrac{-b\pm\sqrt{b^2-4ac}}{2a} \quad\rightarrow\quad x=\cfrac{-0\pm\sqrt{0^2-4\cdot (-4) \cdot1} }{2\cdot (-4) } \:\rightarrow\:\: x=\cfrac{-0^2 \pm4}{2 \cdot(-4)}    $}}  

                                                                                                                         

                                                             \huge {\text {$ \sf \downarrow$}}

                                                                                                         

           \large {\text {$\sf {\bf x_1} = \cfrac{-0+4}{2\left(-4\right)}= \cfrac{-1}{2}  $}}                        \large {\text {$\sf {\bf x_2 }=\cfrac{-0-4}{2\left(-4\right)} = \cfrac{1}{2}  $}}

  • At this point, we're going to add the values ​​of x₁ and x₂:

\large {\boxed {\boxed { \bf x_1 + x_2=  -\cfrac{1}{2}+ \cfrac{1}{2} = 0}  }}

                                           \huge {\text {$ \it  Alternative \: A $}}

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3 years ago
J. Hartley pool builders charge $16,684 to build a residential swimming pool. Their costs are $1,772 for excavation and steel re
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Answer:

$6,592

Step-by-step explanation:

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16,684 - (1772+1024+2793+1541+2962)

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The solution is in the attachment

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