Answer:
303.95 m^3
Step-by-step explanation:
Volume = πr2h
r= 4.4
h = 5
= 3.14 × 4.4^2 × 5
= 3.14 × 19.36 × 5
= 303.95
Hence the volume is 303.95 m^3
1 Simplify a-3a+5a−3a+5 to -2a+5−2a+5
-2a+5-(-a+2b+3)−2a+5−(−a+2b+3)
2 Simplify brackets
-2a+5+a-2b-3−2a+5+a−2b−3
3 Gather like terms
(-2a+a)+5-2b-3(−2a+a)+5−2b−3
4 Simplify
-a+5-2b-3−a+5−2b−3
5 Simplify
-a-2b+2−a−2b+2
Answer:
elasticity supply of dog food = 2.61
elasticity supply of cat food = 1.71
Step-by-step explanation:
The midpoint formula for elasticity is:
![Elasticity = \frac{(Q2-Q1)/[(Q2+Q1)/2]}{(P2-P1)/[(P2+P1)/2]}](https://tex.z-dn.net/?f=Elasticity%20%3D%20%5Cfrac%7B%28Q2-Q1%29%2F%5B%28Q2%2BQ1%29%2F2%5D%7D%7B%28P2-P1%29%2F%5B%28P2%2BP1%29%2F2%5D%7D)
Point 1: Q = 39.0 and P = 5.50
Point 2: Q = 101.0 and P = 7.75
![Elasticity\ supply\ of\ dog\ food = \frac{(101.0-39.0)/[101.0+39.0)/2]}{(7.75-5.50)/[(7.75+5.50)/2]}=2.61](https://tex.z-dn.net/?f=Elasticity%5C%20supply%5C%20of%5C%20dog%5C%20food%20%3D%20%5Cfrac%7B%28101.0-39.0%29%2F%5B101.0%2B39.0%29%2F2%5D%7D%7B%287.75-5.50%29%2F%5B%287.75%2B5.50%29%2F2%5D%7D%3D2.61)
Doing the same for the cat food:
![Elasticity\ supply\ of\ cat\ food = \frac{(71.0-39.0)/[71.0+39.0)/2]}{(7.75-5.50)/[(7.75+5.50)/2]}=1.71](https://tex.z-dn.net/?f=Elasticity%5C%20supply%5C%20of%5C%20cat%5C%20food%20%3D%20%5Cfrac%7B%2871.0-39.0%29%2F%5B71.0%2B39.0%29%2F2%5D%7D%7B%287.75-5.50%29%2F%5B%287.75%2B5.50%29%2F2%5D%7D%3D1.71)
Answer:
<h3>D. P = 15 and Q = 15</h3>
Step-by-step explanation:
Put the values of P and Q to the equation Px - 45 = Qx + 75:
15x - 45 = 15x + 75 <em>subtract 15x from both sides</em>
-45 = 75 FALSE
In other cases, we get some value x.
Example:
A. P = -45 and Q = -75
-45x - 45 = -75x + 75 <em>add 45 to both sides</em>
-45x = -75x + 120 <em>add 75x to both sides</em>
25x = 120 <em>divide both sides by 25</em>
x = 4.8
No they are not equivalent to one another because in order to get from 6to 42 you have to multiply by 7 but to get from 11to 88you have to multiply by 8 . In order for to ratio to equivalent they must have the same factors
