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Rufina [12.5K]
3 years ago
7

The graph shows the pizza orders taken at a pizza shop during lunchtime one day.

Mathematics
1 answer:
miv72 [106K]3 years ago
6 0
B cause it's true if you look at the graph
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Help! I will Mark Brainliest!
Lemur [1.5K]

Answer:

Your answer is B. I had some help from my mom.

Step-by-step explanation:

the average rate of change on the interval [1, 2] is found by computing

 (f(2) - f(1))/(2 - 1)

 = ((4^1+2) - (4^0+2)/1

 = (6-3)

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5 0
2 years ago
Seclate all the numbers that are solutions to the inequalitt w>1.
natima [27]

Answer:

The numbers should be A. 5 and C. 0.

Hope I Helped

6 0
2 years ago
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¿Cuál es el resultado de (-2)(-3)*(-1)x 5?<br>​
podryga [215]
=-30
-2*-3=6
-1*5=-5
6 x -5=-30
8 0
2 years ago
What is the value of 4x - 7 when x = 4<br><br> 1<br> 9<br> 16<br> 23
inn [45]

Answer:

(4×4)_7

16_7

=9 as the answer

7 0
2 years ago
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Question regarding logarithms.
Eddi Din [679]

5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}

\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}

\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}

6 0
3 years ago
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