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3 years ago

What is the square root of 5647

Mathematics

1 answer:

lubasha [3.4K]3 years ago

7 0

<span>75.146523539 is the answer</span>

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How would I find all real solutions in x^4/3 -10^2/3 +21= 0

Oxana [17]

Answer:

Step-by-step explanation:

This equation looks complicated.We have to make it easier

let's say x^2/3 = t and x^4/3 = t^2

t^2-10t+21=0 [ we can factorize this equation as a (t-3)(t-7) ]

(t-3)(t-7)=0 [ that means , t can be 3 or 7 ]

But don't forget we have to find x not t so,

t=x^2/3=3 ∛ x^2 = 3 x^2 = 9 x=3 or x= -3

t=x^2/3=7 ∛x^2 = 7 x^2 = 343 x ~18.5 or x ~ -18.5

7 0

2 years ago

What is 27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5 <br> Answer this fast please!

Dimas [21]

Answer:

86.16

Step-by-step explanation:

27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5

PEMDAS

Multiply and divide first

3/3 is 1 and 75/5 = 15

Replace these into the equation

27+1 +4-1+72.4-34.24+6-4+15

Then add and subtract from left to right

31 +72.4-34.24+6-4+15

69.16+6-4+15

86.16

7 0

2 years ago

Read 2 more answers

the price of three different bags of cat food are shown in the table to the right. Which bags has the lowest price per pound? si

Ksivusya [100]

Answer:

UR MOM

Step-by-step explanation:

STIL YOUR MOM

5 0

3 years ago

Solve the following inequality. Then place the correct answer in the box provided. Answer in terms of a mixed number. 2(P +1) +

Darina [25.2K]

Answer:

$P>-\frac{6}{5}$

Step-by-step explanation:

Isolate the variable by dividing each side by factors that dont't contain the variable.

$2(P+1)+3(P+2)>2$

$2P+2+3P+6>2$

$5P+8>2$

-8 -8

$5P>-6$

Divide both sides by 5.

$P>-\frac{6}{5}$

6 0

2 years ago

Use the fact that the mean of a geometric distribution is μ= 1 p and the variance is σ2= q p2. A daily number lottery chooses th

butalik [34]

Answer:

a). The mean = 1000

The variance = 999,000

The standard deviation = 999.4999

b). 1000 times , loss

Step-by-step explanation:

The mean of geometric distribution is given as , $\mu = \frac{1}{p}$

And the variance is given by, $\sigma ^2=\frac{q}{p^2}$

Given : $p=\frac{1}{1000}$

= 0.001

The formulae of mean and variance are :

$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

a). Mean = $\mu = \frac{1}{p}$

= $\mu = \frac{1}{0.001}$

= 1000

Variance = $\sigma ^2=\frac{1-p}{p^2}$

= $\sigma ^2=\frac{1-0.001}{0.001^2}$

= 999,000

The standard deviation is determined by the root of the variance.

$\sigma = \sqrt{\sigma^2}$

= $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000 times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

= $ 0.50

Since the answer is negative, we are expected to make a loss.

4 0

2 years ago