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OLga [1]
3 years ago
8

How to you write the number 5,000,000,000,000,000,000,000,000,000,000

Mathematics
2 answers:
den301095 [7]3 years ago
6 0
Well, the word form would be five-nonillion.
I hope I helped! =D
tresset_1 [31]3 years ago
5 0
The way you wrote it is how you write it unless you want to do scientific notation then the answer would be, 5x10^30 because for it to be in scientific notation it has to be between 10 and 1 so I moved the decimal spot over 30 to get it into scientific notation. Hope this helps out.
You might be interested in
What is the solution to the following system densations?
givi [52]

Answer:

D. (2, 1)

Step-by-step explanation:

Given:

y = 6x - 11

-2x - 3y = -7

Required:

Find the solution.

Solution:

y = 6x - 11 ---› eqn. 1

-2x - 3y = -7 ----› eqn 2

Substitute y = (6x - 11) into equation 2.

-2x - 3(6x - 11) = -7

-2x - 18x + 33 = -7

-20x + 33 = -7

Subtract 33 from each side

-20x = -7 - 33

-20x = -40

Divide both sides by -20

x = -40/-20

x = 2

Substitute x = 2 into equation 1.

y = 6x - 11 ---› eqn. 1

y = 6(2) - 11

y = 12 - 11

y = 1

The solution is very (2, 1)

7 0
3 years ago
6. At what intervals is the function g(x) shown below increasing and/or decreasing?
gizmo_the_mogwai [7]
Decreasing [-8, -4] increasing [-1, 2]

(look at the slopes)
4 0
3 years ago
I need help please,​
Luba_88 [7]

Answer: -7

Step-by-step explanation:

trust me

7 0
3 years ago
Read 2 more answers
X + 2y = 10<br><br> y=x-4<br> Choices are:<br> (0,4)<br> (2,6)<br> (6,2)<br> (8,0) <br> Work shown
LuckyWell [14K]

Answer:

C) (6,2)

Step-by-step explanation:

Rewrite equations:

y=x−4;x+2y=10

Step: Solve y=x−4for y:

y=x−4

Step: Substitute x − 4 for y in x+2y=10:

x+2y=10

x+2(x−4)=10

3x−8=10(Simplify both sides of the equation)

3x−8+8=10+8(Add 8 to both sides)

3x=18

3x

3

=

18

3

(Divide both sides by 3)

x=6

Step: Substitute6forxiny=x−4:

y=x−4

y=6−4

y=2(Simplify both sides of the equation)

Hope this helps!

:)

5 0
3 years ago
Read 2 more answers
What expression is equivalent to? Screenshots attached. Please help!
Galina-37 [17]

Answer:

the correct option is C i.e. 8x^4yz^4\sqrt{2yz}

Step-by-step explanation:

We need to solve the expression :

\sqrt{128x^8y^3z^9}

Factors of 128 are: 2x2x2x2x2x2x2

and we know √ = 1/2

and √a.b = √a.√b

Solving:

=\sqrt{128x^8y^3z^9}\\\\=\sqrt{128} \sqrt{x^8} \sqrt{y^3} \sqrt{z^9}\\=\sqrt{2x2x2x2x2x2x2}\sqrt{x^8} \sqrt{y^2.y} \sqrt{z^8.z}\\=\sqrt{2^2x2^2x2^2x2}\sqrt{x^8} \sqrt{y^2.y} \sqrt{z^8.z}\\=(2^2)^{1/2} (2^2)^{1/2}(2^2)^{1/2} (2)^{1/2} (x^8)^{1/2} (y^2)^{1/2} (y)^{1/2} (z^8)^{1/2} z^{1/2}\\=2.2.2.(2)^{1/2}x^4y(y)^{1/2}z^4(z)^{1/2}\\=8x^4yz^4\sqrt{2yz}

So, the correct option is C i.e. 8x^4yz^4\sqrt{2yz}

7 0
3 years ago
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