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gtnhenbr [62]
3 years ago
10

PLZ HELPPP<br />

Mathematics
1 answer:
Alexeev081 [22]3 years ago
6 0
V=vanila
c=chocolate

4v+1c=45
v+c=27

mulitply 2nd equation by -1 and add to top one

-v-c=-27
<u>4v+1c=45 +</u>
<u />3v+0c=18

3v=18
divide by 3
v=6

sub back
v+c=27
6+c=27
c=21

21 choc and 6 van





A.
v+c=27
4v+1c=45
v=number of vanila wafers bought
c=number of chocolate wafers bought

B. 21 chocolate and 7
I got the answer with math because math is fun and tada
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Which of the following relations are not functions? Select all that apply.  {(1, 3), (3, 7), (5, 11), (7, 15), (9, 19)}  {(1,
zavuch27 [327]

Given:

7 relations are given.

To find:

The relation which is not a function.

Step-by-step explanation:

A relation is called function if there exist unique output for each input.

It means, each x-value has only one y-value.

{(1, 3), (3, 7), (5, 11), (7, 15), (9, 19)}, it is a function.

{(1, 3), (1, 7), (5, 11), (5, 15), (9, 19)}, it is not a function because there exist two y-values y=3 and y=7 at x=1.

{(−2, 4), (−1, 1), (0, 0), (1, 1), (2, 4)}, it is a function.

{(2, 4), (1, 1), (0, 0), (1,−1), (2, −4)},it is not a function because there exist two y-values y=4 and y=-4 at x=2.

{(6, 3), (4, 1), (2, 1), (0,−1), (−2,−3)}, it is a function.

{(1, 3), (3, 7), (3, 11), (7, 15), (9, 19)}, it is not a function because there exist two y-values y=7 and y=11 at x=3.

{(1, 3), (3, 7), (5, 11), (9, 15), (9, 19)}, it is not a function because there exist two y-values y=15 and y=19 at x=9.

Therefore, the correct options are 2, 4, 6 and 7.

8 0
3 years ago
thirty five percent of the revenue produced at the auction will go to the charity. the morning participants spent an average of
spin [16.1K]
I'm not sure that I am 100% right but I'll give it a shot.
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$43.75

4 0
3 years ago
Please help me. I'm stupid.
Gwar [14]

Answer:

\displaystyle 36\:units

Step-by-step explanation:

Split up this Isosceles, Right Triangle into two congruent smaller right triangles. The reflexive side [the line that splits them apart] is 6 units, and both legs are 8 units, leaving the hypotenuses to AUTOMATICALLY be 10 units, according to the Pythagorean Theorem:

\displaystyle a^2 + b^2 = c^2 \\ \\ 6^2 + 8^2 = 10^2 \\ \\ 36 + 64 = 100 \\ \\ 100 = 100

With this Pythagorean Triple, we know that our dimensions are correct. Now, to find the perimeter, just add up all the sides EXCEPT for the divider:

\displaystyle 2[10] + 2[8] = 20 + 16 = 36

I am joyous to assist you anytime.

3 0
3 years ago
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Since it starts with 2 envelopes, subtract 2 from 17 to get how many and in all 3 packs.
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