2 years ago

PLZ HELPPP<br />

1 answer:

6 0

V=vanila
c=chocolate

4v+1c=45
v+c=27

mulitply 2nd equation by -1 and add to top one

-v-c=-27
<u>4v+1c=45 +</u>
<u />3v+0c=18

3v=18
divide by 3
v=6

sub back
v+c=27
6+c=27
c=21

21 choc and 6 van

A.
v+c=27
4v+1c=45
v=number of vanila wafers bought
c=number of chocolate wafers bought

B. 21 chocolate and 7
I got the answer with math because math is fun and tada

You might be interested in

PLS HELP!! WILL GIVE BRAINLIEST!

Elodia [21]

Answer:

The lower quartile of Class A is greater than the lower quartile of Class B.

Class A has a Greater number of lower quartiles then Class B as the imagie shows. Class A has 65-75 while class B has 70-75.

3 0

2 years ago

The sum of the squares of two consecutive negative integers is 61. Find the smaller of the two integers

Marysya12 [62]

$x^2+(x+1)^2=61\\ x^2+x^2+2x+1-61=0\\ 2x^2+2x-60=0\ \ /:2\\ x^2+x-30=0\\ \Delta=1^2-4\cdot(-40)=1+120=121\ \ \Rightarrow\ \ \sqrt{\Delta} =11\\ \\ x_1= \frac{-1-11}{2} = \frac{-12}{2} =-6,\ \ \ \ x_2= \frac{-1+11}{2} = \frac{10}{2}=5\\ \\Ans.:x=-6$