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3 years ago

Find the value of y.

Mathematics

1 answer:

myrzilka [38]3 years ago

6 0

Answer:

i think it's D

Step-by-step explanation:

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Find the equation of a line containing the following points. Write the equation in slope-intercept form.

Sindrei [870]

Answer:

y=1/4x + 1.75

Step-by-step explanation:

1-2/2--2 = 1/4

2=1/4+b

b=1.75

8 0

3 years ago

Need help with slope line.

klio [65]

y-1=-2(x-4)

simplifies to

y-1=-2x-8

4 0

3 years ago

xz_007 [3.2K]

Answer:

$Center = \boxed{1}, \: \boxed{ - 2} \: ; \: Radius = \boxed{3}$

Step-by-step explanation:

${x}^{2} + {y}^{2} - 2x + 4y - 4 = 0 \\ \\ ({x}^{2} - 2x + 1 - 1) + ( {y}^{2} + 4y + 4 - 4) - 4 = 0 \\ \\ ( {x}^{2} - 2x + 1) + ( {y}^{2} + 4y + 4) - 9 = 0 \\ \\ {(x - 1)}^{2} + {(y + 2)}^{2} = 9 \\ \\ {(x - 1)}^{2} + {(y + 2)}^{2} = {3}^{2} \\ \\ equating \: it \: with \\ \\ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\ \\ h = 1 \\ k = - 2 \\ r = 3 \\ \\ center = \boxed{1} \: \boxed{ - 2} \: \: radius = \boxed{3}$

3 0

3 years ago

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$

so, $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

since $\sqrt{3}=1.732$

so, $(6+7(1.732),0)\text{ and }(6-7(1.732),0)$ are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0

3 years ago

Can someone solve this? Number 25 only please.

V125BC [204]

0.06x0.06 = 0.0036

dont wory about the zeros just the actual numbers than add the zeros

6 0

3 years ago