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erica [24]
3 years ago
8

Solve 9,159 divided by 7

Mathematics
2 answers:
hodyreva [135]3 years ago
7 0

Answer:

9,159 divided by 7 is 1308.

<u><em>I hope this helped at all.</em></u>

aniked [119]3 years ago
5 0

Answer:

(9159 / 7 = 1308.429)

Step-by-step explanation:

Simply multiply the last digit by 2 and then subtract the product from the remaining digits.

If that difference is divisible by 7, then 9159 is divisible by 7.

The last digit in 9159 is 9 and the remaining digits are 915. Thus, the math to determine if 9159 is divisible by 7 using our alternate method is:

915 - (9 x 2) = 897

Since 897 is not divisible by 7, 9159 is also not divisible by 7.

Therefore, the answer to "Is 9159 Divisible By 7?" is no.

(9159 / 7 = 1308.429)

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Find the area of the given triangle to the nearest square unit. Angle a= 30 degrees, b=10, angle B=45 degrees
storchak [24]

Answer:

A=34\ units^2

Step-by-step explanation:

Suppose we have a general triangle like the one shown in the figure.

We know the angle A, the angle B and the length b.

A = 30\°\\\\B = 45\°\\\\b = 10

By definition I know that the sum of the internal angles of a triangle is always equal to 180 °.

So

A + B + C = 180\\\\30 + 45 + C = 180

We solve the equation and thus we find the angle C.

C = 180 - 30-45\\\\C = 105

We already know the three triangle angles.

Now we use the sine theorem to calculate the sides c and a.

The  sine theorem says that:

\frac{sin(A)}{a}=\frac{sin(B)}{b}=\frac{sin(C)}{c}

Then

\frac{sin(30)}{a}=\frac{sin(45)}{10}

\frac{sin(30)}{\frac{sin(45)}{10}}=a

a=7.071

Also

\frac{sin(105)}{c}=\frac{sin(45)}{10}

\frac{sin(105)}{\frac{sin(45)}{10}}=c

c=13.660

Finally, we use the Heron formula to calculate the triangle area

A=\sqrt{s(s-a)(s-b)(s-c)}

Where s is:

s=\frac{a+b+c}{2}

Therefore

s=\frac{7.071+10+13.660}{2}

s=15.37

A=\sqrt{15.37(15.37-7.071)(15.37-10)(15.37-13.66)}

A=34\ units^2

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Step-by-step explanation:

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Answer:

See below

Step-by-step explanation:

We want to prove that

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Taking the RHS, note

\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}

Remember that

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Read 2 more answers
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