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agasfer [191]
3 years ago
9

SIMPLIFY THE EXPRESSION

Mathematics
1 answer:
ankoles [38]3 years ago
8 0

Answer:

D

Step-by-step explanation:

when you have the same bases but different exponents, for example (X ^ 3 / X ^ 1) = (X ^ 2) this should be the same in the problem for each one with (r, s, t)

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The Foley Products Company has designed a new blend of concrete they believe will be twice as strong as their current high quali
Hitman42 [59]

Answer:

All of the batches of the new blend of concrete made at their plant in a particular week.

Step-by-step explanation:

The population refers to all the subjects or data which which meets the condition or requirement of a certain experiment or research. This means that all the set of similar items or subjects which is of interest in a certain study is the population. In the scenario above, the population will be the set of all the new blend concrete which are made in the plant within a certain week. Thereafter, if a sample is required it will be drawn from these set of data or observation.

8 0
2 years ago
Last month you spent $30 on clothing. This month you spent 150% of what you spent last month. How much did you spend this month?
Ann [662]

Answer:

Last moth I spent $45 on clothing.

Step-by-step explanation:

To solve this problem, we just need to find 150% of $30.

30 x 1.50 = 45

Therefore, last moth I spent $45 on clothing.

Hope this helps! :D

3 0
3 years ago
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Mai had 5 candy bars. She ate half of one candy bar and decided to distribute the remaining bars between her two sisters and her
brilliants [131]
1 and 2/3 is the answer
7 0
3 years ago
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18y^8x^4w^6 and 30y^7w^3
djyliett [7]

Answer:

10

Step-by-step explanation:

6 0
3 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
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