For any two nonzero integers the product and quotient have the same sign.

1 answer:

8 0

<span>This statement is always true. For any two nonzero integers the product and quotient have the same sign. For example, -2*-3 = 6 and of we see -2/-3, then the result is 2/3. The sign in the result is same after product and quotient, but the result has the same sign.</span>

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PLEASE HELP!!!!!!!!!!!!!!!!!

Nookie1986 [14]

The answer is 2 3/10. how do you not know this

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3 years ago

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-4 times a number plus 16 is -116. find the number and show work.

pav-90 [236]

-4*25 = -100+16 = -116

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3 years ago

Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams

hram777 [196]

Answer:

$X(16)=25.71grams$

Step-by-step explanation:

let $X(t)$ denote grams of $C$ formed in $t$ mins.

For $X grams$ of $C$ we have:

$\frac{2}{3}Xg$ of A and $\frac{1}{3}Xg$ of B

Amounts of A,B remaining at any given time is expressed as:

$40-\frac{2}{3}Xg$ of A and $50-\frac{1}{3}Xg$ of B

Rate at which C is formed satisfies:

$\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}$