Answer:
True
Explanation:
The linkage relation of two genes can be determined on the basis of calculating recombination frequency.
If the recombination frequency value is greater than 50% then the genes are not linked and if the value is less than 50% then the genes are linked.
In the given question, the crossover gametes formed will be Ab = 100
and aB= 106.
Therefore,
Since the recombinant frequency value is larger than 50% therefore the genes do not show linkage.
Thus, True is the correct answer.
The answer is an abdominal cavity.
The abdominal cavity refers to a space that comprises various essential organs including the stomach, the lower part of the esophagus, colon, small intestine, gallbladder, liver, rectum, bladder, spleen, and kidneys.
The abdominal cavity is a big cavity found in humans and various other animals. It is a component of abdominopelvic cavity. It is situated above the pelvic cavity and below the thoracic cavity. Its dome-shaped roof is the thoracic diaphragm, a thin sheet of muscles beneath the lungs, and its floor is the pelvic inlet, opening into the pelvis.
Answer:
so they can fly obviously