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Luba_88 [7]
3 years ago
9

What two consecutive integers have a sum of 75?

Mathematics
2 answers:
snow_lady [41]3 years ago
8 0

Answer:

37 and 38

Step-by-step explanation:

Let the two consecutive integers be x and x+1

According to the question,

sum of the two consecutive integers is 75

Therefore,

x +(x+1)= 75

=>2x+1=75

=>2x=75-1

=>2x=74

=>x=74/2

=>x=37

So, the two numbers are 37 and (37+1)

=37 and 38

marshall27 [118]3 years ago
7 0

Answer:

37 and 38.

Step-by-step explanation:

Let the smaller integer be x.

Thus, the larger integer is (x+1) since it is consecutive.

x+(x+1)=75

2x+1=75

Subtract both sides by 1:

2x+1-1=75-1

2x=74

Divide both sides by 2:

\frac{2x}{2}=\frac{74}{2}

x=37

To find the other number, simply add 1 to 37 to get 38.

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Explanation:

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We don't know the value of lowercase 'a', so we'll ignore the sin(A)/a portion.

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We see that one side is 2 cm long, so this means b = 2. The angle opposite this is 105 degrees, so B = 105.

The angle opposite side c is 15 degrees, so C = 15.

The lowercase letters represent side lengths, while the uppercase letters are angles.

--------------------------

We have enough to apply the law of sines to solve for side c.

sin(B)/b = sin(C)/c

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