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Luba_88 [7]
3 years ago
9

What two consecutive integers have a sum of 75?

Mathematics
2 answers:
snow_lady [41]3 years ago
8 0

Answer:

37 and 38

Step-by-step explanation:

Let the two consecutive integers be x and x+1

According to the question,

sum of the two consecutive integers is 75

Therefore,

x +(x+1)= 75

=>2x+1=75

=>2x=75-1

=>2x=74

=>x=74/2

=>x=37

So, the two numbers are 37 and (37+1)

=37 and 38

marshall27 [118]3 years ago
7 0

Answer:

37 and 38.

Step-by-step explanation:

Let the smaller integer be x.

Thus, the larger integer is (x+1) since it is consecutive.

x+(x+1)=75

2x+1=75

Subtract both sides by 1:

2x+1-1=75-1

2x=74

Divide both sides by 2:

\frac{2x}{2}=\frac{74}{2}

x=37

To find the other number, simply add 1 to 37 to get 38.

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7/18

Step-by-step explanation:

4 2/3=14/3

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reduces to

7/18

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2 years ago
The sum of three consecutive even numbers is 66. What is the smallest of these numbers?​
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Step-by-step explanation:

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Solve the math riddle below
Tju [1.3M]

Answer:

28 eggs

Step-by-step explanation:

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I'm having trouble figuring out what the equation is for the trend line and what the slope is
Talja [164]

Answer:

The equation for the trend line would be y = -1/100x + 25

Step-by-step explanation:

In order to find the trend line, we first need to find the slope. To do so, we need to find two points on the line. The points we'll use are (0, 25) and (2500, 0). Next, we use the slope formula.

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m = (0 - 25)/(2500 - 5)

m = -25/2500

m = -1/100

Now that we have this we can use the slope and the intercept in slope intercept form to model the trend line.

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3 0
3 years ago
In one jar, I have two balls labelled 1 and 2 respectively. In a second jar, I have three balls labelled 0, 1 and 2 respectively
PolarNik [594]

Step-by-step explanation:

this is a kind of trick question, actually.

with whatever we draw, we produce X values as power of 3.

to be precise, we can have only

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so, we are looking at the probability to get 0 as multiplication result of the numbers on the 2 drawn balls.

the only possibilities are

1 and 0

2 and 0

out of in total 6 (2×3) different outcomes

1 and 0

1 and 1

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2 and 0

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the probability of this "0" event is again

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