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Luba_88 [7]
3 years ago
9

What two consecutive integers have a sum of 75?

Mathematics
2 answers:
snow_lady [41]3 years ago
8 0

Answer:

37 and 38

Step-by-step explanation:

Let the two consecutive integers be x and x+1

According to the question,

sum of the two consecutive integers is 75

Therefore,

x +(x+1)= 75

=>2x+1=75

=>2x=75-1

=>2x=74

=>x=74/2

=>x=37

So, the two numbers are 37 and (37+1)

=37 and 38

marshall27 [118]3 years ago
7 0

Answer:

37 and 38.

Step-by-step explanation:

Let the smaller integer be x.

Thus, the larger integer is (x+1) since it is consecutive.

x+(x+1)=75

2x+1=75

Subtract both sides by 1:

2x+1-1=75-1

2x=74

Divide both sides by 2:

\frac{2x}{2}=\frac{74}{2}

x=37

To find the other number, simply add 1 to 37 to get 38.

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(x-y) (x-1,y+3) (I need the answer pls)
SVEN [57.7K]

Answer:

x² - 2xy + 3x + y² - 3y

Step-by-step explanation:

1: Multiply the second parentheses by each term from the first parentheses

X x(x - 1 y + 3) - y x (x - 1y + 3)

2: Distribute x through parentheses

4 0
4 years ago
In 1990 the average family income was about $ 39 , 000 , and in 2010 it was about $ 70 , 768 . Let x = 0 represent 1990, x = 1 r
iren2701 [21]

Answer:

<em />f(x) = 1588.4x + 39000<em />

f(15) = 62826

Step-by-step explanation:

Given

In 1990; Income= $39000

In 2010; Income= $70768

Solving (a): An equation in form of f(x) = ax + b

First, we need to determine the slope, a

a = \frac{y_2 - y_1}{x_2 - x_1}

Taking y as income and x as year index.

When x = 0; y = 39000

When x = 20; y = 70768

Substitute these values in the above formula

a = \frac{70768 - 39000}{20 - 0}

a = \frac{31768}{20}

a = 1588.4

Next, is to determine the formula using:

y - y_1 = a(x - x_1)

<em>Considering :When x = 0; y = 39000, we have</em>

<em />y - 39000 = 1588.4(x - 0)<em />

<em />y - 39000 = 1588.4x<em />

<em>Make y the subject of formula</em>

<em />y = 1588.4x + 39000<em />

<em />

<em>Express y as a function of x</em>

<em />f(x) = 1588.4x + 39000<em />

Solving (b): Income in 2005

<em>In 2005, x = 15</em>

So:

f(x) = 1588.4x + 39000 becomes

f(15) = 1588.4 * 15 + 39000

f(15) = 62826

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