Answer:
i
Step-by-step explanation:
Answer:
102
Step-by-step explanation:
These angles are congruent due to corresponding angles thm
3x + 21 = 6x - 60
3x - 6x = -60 - 21
-3x = -81
x = 27
3x + 21
3(27) + 21
81 + 21
102
Amount of fuel in the tank before the story begins . . . . . zero.
Total amount poured in . . . . . 3/4 gallon.
Total amount burned:
on Friday . . . . . 1/4 gallon
on Sunday . . . . 1/4 gallon
Total used . . 1/2 gallon .
Amount remaining in the tank on Monday:
(3/4 gallon in) - (1/2 gallon burned) = 1/4 gallon left.
==> NOT empty
The tank would have been empty on Monday IF Becky
had poured in only 1/2 gallon, instead of 3/4 of a gallon
before the first flakes began to fly.
Okay, the image is a little tough to see, but I believe it looks something like this:
(5² -10 / 17 - 3 * 4) -1
The first step [remember PEMDAS] is parentheses
Next comes Exponents:
(25 - 10 / 17 - 3 * 4) -1
Then Multiplication:
(25 - 10 / 17 - 12) - 1
Then Division [which we can't do yet since it isn't fully simplified], so we skip to Addition... nothing again, then subtraction.
(15 / 5) - 1
Then we can divide:
(3) - 1
Then subtract!
2
The answer to your problem is 2.
Hope that helps!
Check the picture below.
since in a rhombus the diagonals bisect each other, thus EC = EA.
now, the rhombus is simply 4 congruent triangles, we know the base and height of one of them, thus
![\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=8\\ h=15 \end{cases}\implies A=\cfrac{1}{2}(8)(15)\implies A=60 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of all 4 triangles}}{4(60)\implies 240}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20triangle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dbh~~%20%5Cbegin%7Bcases%7D%20b%3D8%5C%5C%20h%3D15%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%288%29%2815%29%5Cimplies%20A%3D60%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20all%204%20triangles%7D%7D%7B4%2860%29%5Cimplies%20240%7D)