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3 years ago

6

Which of the equations below shows the relationship in the table? [X] [15] [5] [3] [1] -----------------------------------------

- [Y] [1] [3] [5] [15]] A. y = 15x B. y = x - 14 C. y = x + 2 D. y = 15 x

1 answer:

Nataly_w [17]3 years ago

4 0

Y=15/x or xy=15 it seems that a should be 15/x

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What is proppotion of 10/15 =12/x?

Marianna [84]

12 divided by 10 is 1.2. 15 multiplied by 1.2 is 18 so x equals 18

7 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

4 years ago

Find the volume of this sphere.<br> Use 3 for TT.<br> V ≈ [?]in³<br> V = πr³<br> 5in<br> Entering

nydimaria [60]

Answer:

500

Step-by-step explanation:

r = 5

r³ = 125

V = (4/3)pi(r³)

pi = 3

V = (4/3)3(125)

/3 and x3 cancel

V = 4 x 125

V = 500

6 0

2 years ago

Write 0.000700804 in scientific notation please

klasskru [66]

Multiply the 0.00070080 by 10, 4 times, making it a 7.008. When you multiply each time by 10 it moves the decimal point to the right one time. To keep the number the same you put x10 to the 4th power next to the 7.008. This makes your answer 7.008x10 to the negative 4th power.

Hope I could help! :)

5 0

3 years ago

Tom and Jane left for school, Tom walked to school on route A which was 4.5 kilometers while Jane walked to school on route B wh

Aleonysh [2.5K]

Answer:

3.95 km

Step-by-step explanation:

The computation is shown below:

As both left for school

Tom walked to school on route A i.e. 4.50 kilometer

And, Jane walked to school on route B i..e 8 kilometers & 450 meters i.e. 8.45 kilometers

So, the more km that jane would take to reach to school as compared with Tom is

= 8.45 km - 4.50 km

= 3.95 km

4 0

3 years ago