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Yuki888 [10]
3 years ago
11

roy is going to increase the size of his patio to make room for a new bbq grill. The ratio of the area of the old patio to the a

rea of the new patio is 2 1/4 : 6 3/4. Convert this ratio to a unit rate and explain what this unit rate means in the context of this problem.
Mathematics
2 answers:
Vaselesa [24]3 years ago
6 0
We are going to rewrite the ratio.
 We have:
 2 1/4: 6 3/4
 = (2 + 1/4) / (6 + 3/4)
 = (2.25) / (6.75)
 = (225/100) / (675/100)
 = (45/20) / (135/20)
 = (9/4) / (27/4)
 = 9/27
 = 3/9
 = 1/3
 Therefore, we have:
 A1 / A2 = 1/3
 A2 = 3A1
 A1: old patio
 A2: new patio
 Answer:
 
The area of the new patio is three times larger than the area of the old patio.
Yanka [14]3 years ago
6 0

Answer:

1/3

Step-by-step explanation:

2 1/4 divided by 6 3/4

9/4 multiplied 27/4

Cross cancel

1/3

Sorry, this is a late answer.

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tekilochka [14]

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2 years ago
Can anyone please help??
Igoryamba
There are infinite numbers

7 0
3 years ago
Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure
Marina CMI [18]

Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

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3 years ago
Read 2 more answers
Please help me with this!
Airida [17]

Step-by-step explanation:

→ 42 = 7u - u

→ 42 = 6u

→ 42/6 = u

→ 7 =u or U = 7

<em><u>hope </u></em><em><u>this</u></em><em><u> answer</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> dear</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care </u></em><em><u>and</u></em><em><u> may</u></em><em><u> u</u></em><em><u> have</u></em><em><u> a</u></em><em><u> great</u></em><em><u> day</u></em><em><u> ahead</u></em><em><u>!</u></em>

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52% decrease hope this helps!!
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