The price of the car increased by 10%.
Hope this helps
To write something in percent form, find out what the numerator becomes when the denominator is equal to 100. Add a percent sign to the numerator and you get the fraction in percent form.
In
![\frac{7}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B7%7D%7B20%7D%20)
we can multiply the fraction by 5 to make the denominator 100. The numerator will be 35. So the answer is
35%.
Step-by-step explanation:
Formula:- 4/3*Pi*r^3
= 4/3*22/7*(1/2)^3
Please mark me as brainliest
Given:
The height of the given trapezoid = 6 in
The area of the trapezoid = 72 in²
Also given, one base of the trapezoid is 6 inches longer than the other base
To find the lengths of the bases.
Formula
The area of the trapezoid is
![A=\frac{1}{2} (b_{1} +b_{2} )h](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%20%28b_%7B1%7D%20%2Bb_%7B2%7D%20%29h)
where, h be the height of the trapezoid
be the shorter base
be the longer base
As per the given problem,
![b_{2}=b_{1} +6](https://tex.z-dn.net/?f=b_%7B2%7D%3Db_%7B1%7D%20%20%2B6)
Now,
Putting, A=72,
and h=6 we get,
![\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%28b_%7B1%7D%20%2Bb_%7B1%7D%2B6%29%286%29%20%3D%2072)
or, ![b_{1}+b_{1}+6 = \frac{(72)(2)}{6}](https://tex.z-dn.net/?f=b_%7B1%7D%2Bb_%7B1%7D%2B6%20%3D%20%5Cfrac%7B%2872%29%282%29%7D%7B6%7D)
or, ![2b_{1}+6 = 24](https://tex.z-dn.net/?f=2b_%7B1%7D%2B6%20%3D%2024)
or, ![2b_{1}=24-6](https://tex.z-dn.net/?f=2b_%7B1%7D%3D24-6)
or, ![b_{1}= \frac{18}{2}](https://tex.z-dn.net/?f=b_%7B1%7D%3D%20%5Cfrac%7B18%7D%7B2%7D)
or, ![b_{1}=9](https://tex.z-dn.net/?f=b_%7B1%7D%3D9)
So,
The shorter base is 9 in and the other base is = (6+9) = 15 in
Hence,
One base is 9 inches for one of the bases and 15 inches for the other base.
Answer:
Step-by-step explanation:
C
l
2
+
2
K
B
r
→
2
K
C
l
+
B
r
2
Given:
300
g
of
C
l
2
300
g
of
K
B
r
(a) Mass of
C
l
2
= 300g
Molecular mass of
C
l
2
= 2(35.45) = 70.906 g
/
m
o
l
No.of moles of
C
l
2
=
m
a
s
s
/
m
o
l
a
r
m
a
s
s
=
300
/
70.906
=
4.23
moles
Mass of
K
B
r
=
300
g
Molar mass of
K
B
r
=
39
+
79.9
=
118.9
g
/
m
o
l
No.of moles of
K
B
r
=
300
/
118.9
=
2.52
moles
Now,
Consider the equation:
C
l
2
+
2
K
B
r
→
2
K
C
l
+
B
r
2
1
mole of
C
l
2
= 2 moles of
K
C
l
4.23
moles of
C
l
2
= 2x4.23=
8.46
moles
2
moles of
K
B
r
= 2 moles of
K
C
l
2.52
moles of
K
B
r
=
2.52
moles
Now convert moles to mass,
Mass of
K
C
l
produced by
C
l
2
=
8.46
×
70.906
=
599.8
g
Mass of
K
C
l
produced by potassium bromide =
2.52
×
74.5
=
187.74
g