Answer:
2.75 seconds.
Step-by-step explanation:
We have been given that a ball is dropped from the ground. T represents the time in seconds.
To find the time when the ball was in air, we will equate height of ball with 0 and solve for t.

Upon dividing both sides by 4, we will get:







Since our given function is a downward opening parabola, so ball will be in air between both t-intercepts.
Since the ball touches the ground at 2.75 seconds, therefore, the ball would be in air for approximately 2.75 seconds.
Since all the edges are 6, then it would be 216 as the volume.
Answer: 6hours and 25 minutes
5/8 of one hour is 37min and 5seconds
Multiple by the 10 evenings is 375
Divide by 60 (minutes in an hour)
Answer:
65
Step-by-step explanation:
median = (N+1)/2
=(100+1)/2
= 50.5
cf just greater than 50.5 is 65 .So, median is 65.
G(x) = 2x² - 5x + 2 = 2x² - 4x - x + 2 = 2x · x - 2x · 2 - 1 · x - 1 · (-2)
= 2x(x - 2) -1(x - 2) = (x - 2)(2x - 1)
g(x) = 0 ⇔ (x - 2)(2x - 1) = 0 ⇔ x - 2 = 0 or 2x - 1 = 0
x = 2 or x = 0.5