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3 years ago

Which congruence theorems can be used to prove △ABR ≅ △ACR? Check all that apply. HL SAS SSS ASA AAS

Mathematics

2 answers:

GaryK [48]3 years ago

8 0

Answer:

HL, SSS, SAS can be used to prove both triangles congruent.

Step-by-step explanation:

In ΔABR And ΔACR we are given following corresponding equal parts,

∠B = ∠C = 90°

AB = AC

BR = CR

AR = AR (common)

1st. ΔABR ≅ ΔACR By HL congruence rule

as Hypotenuse AR = AR & 1 leg AB = AC or BR = CR

2nd ΔABR ≅ ΔACR By SSS congruence rule

as AB = AC & BR = CR & AR = AR (All sides of ΔABR equals to sides of ΔACR)

3rd ΔABR ≅ ΔACR By SAS congruence rule

AB = AC & ∠B = ∠C & BR = CR (2 sides of ΔABR equals to 2 sides of ΔACR and angle between both side are also equal)

ΔABR and ΔACR can not be congruent by ASA & AAS rule because no 2nd equal angle is not given.

Verizon [17]3 years ago

5 0

HL (It's a right triangle and the hypotenuse and leg are congruent. This can also be thought of as SAS.)

SAS (Side angle side. All congruent.)

SSS (Line AR is shared by both triangles. A line is always congruent on itself. The other two are self explanatory.)

ASA and AAS cannot be used because we can only confidently confirm one angle of each triangle.

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3 years ago

Please help! "Indicate the equation of the given line in standard form. The line containing the midpoints of the legs of right t

julsineya [31]

Nice. We're not really told which is the right angle. We can tell from the squared distances:

$AB^2=(1 - -5)^2 + (1-5)^2=6^2+4^2=52$

$BC^2=(3-1)^2+(4-1)^2=2^2+3^2=13$

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That was preliminary and probably indicated in an associated figure.

Now we want the line through the midpoint of the legs, AB and BC, in standard form.

The midpoint of AB is the average of the coordinates of A and B:

$\left( \dfrac{-5 +1}{2}, \dfrac{5+1}{2} \right) = (-2,3)$

The midpoint of BC is

$\left( \dfrac{1 + 3}{2}, \dfrac{1 + 4}{2} \right) = ( 2, \frac 5 2)$

The line through those points is

$(y - 3)(2 - -2)=(x - -2)(\frac 5 2 - 3)$

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$8y - 24 = -x -2$

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That's the answer. Let's check it.

Midpoint of AB is (-2,3), -2 + 8(3)=22 good.

Midpoint of BC is (2,5/2), 2+8(5/2)=22 good.

$\textrm{Answer: } x + 8y = 22$

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3 years ago

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Gnesinka [82]

Answer: Yes. Dominic is correct

Step-by-step explanation:

We are informed that Two fifth of the students wrote a report. This also means that (2/5 × 100) = 40% = 0.4 wrote a report and 0.6 of the students gave a presentation.

From the decimals gotten, we can see that 0.6 is more than 0.4. Therefore, more students gave a presentation. This implies that Dominic is correct.

3 0

3 years ago

HELP ME PLEASE! Thanks

GaryK [48]

-12 because -1*12 =-12

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4 years ago