Answer:
HL, SSS, SAS can be used to prove both triangles congruent.
Step-by-step explanation:
In ΔABR And ΔACR we are given following corresponding equal parts,
∠B = ∠C = 90°
AB = AC
BR = CR
AR = AR (common)
1st. ΔABR ≅ ΔACR By HL congruence rule
as Hypotenuse AR = AR & 1 leg AB = AC or BR = CR
2nd ΔABR ≅ ΔACR By SSS congruence rule
as AB = AC & BR = CR & AR = AR (All sides of ΔABR equals to sides of ΔACR)
3rd ΔABR ≅ ΔACR By SAS congruence rule
AB = AC & ∠B = ∠C & BR = CR (2 sides of ΔABR equals to 2 sides of ΔACR and angle between both side are also equal)
ΔABR and ΔACR can not be congruent by ASA & AAS rule because no 2nd equal angle is not given.