Answer:
(A) Current period productivity= 4 units/hr
Previous period productivity= 3.833units/hr
(B) increase in productivity by 4.356 percent
Explanation:
A manager checkedthe rate of production and found out that a worker produced 160 units while working for 40 hours
In the previous week the same worker produced 138 units while working for 36 hours
(A) The current period productivity can be calculated as follows
= 160 units/40 hours
= 4 units/hr
The previous period productivity can be calculated as follows
= 138 units / 36 hours
= 3.833 units/hr
(B) The productivity growth can be calculated as follows
= current period productivity - previous period productivity / previous period productivity
= 4-3.833/3.833
= 0.167/3.833
= 0.04356 × 100
= 4.356 percent
Hence there was an increase in workers productivity by 4.356 percent
Answer:
7.3%; 12.17%; 0.6 times; 15.95%
Explanation:
Return on assets:
= Net Income ÷ Average total assets
= ($65,700 ÷ $900,000) × 100
=
7.3%
Profit Margin:
= Net Income ÷ Net Sales
= ($65,700 ÷ $540,000) × 100
= 12.17%
Asset Turnover:
= Net Sales ÷ Average Total Assets
= $540,000 ÷ $900,000
= 0.6 times
Return on Equity:
= Net Income before dividend ÷ Equity
= [($65,700 + $30,000) ÷ $600,000] × 100
= ($95,700 ÷ $600,000] × 100
= 15.95%
Answer:
Your answer is going to be c.
Explanation:
as soap is meant to wash away germs it has to first kill them.
Answer:
the correct answer is $150
Explanation:
TC=500 + 150q - 20q^2 + q^3
AVC=(150Q-20Q^2+Q^3)/Q
=150-20Q+Q^2
When AVC is at its minimum means that the marginal cost( CM) is igual to AVC, so we could consider this analysis:
CM= d(TC)/dq =150-40Q+3Q^2
CM=AVC
150-40Q+3Q^2=150-20Q+Q^2
Join similar terms:
150-150-40Q+20Q+3Q^2-Q^2=0
0-20Q+2Q^2=0
Q(-20+2Q)=0
Q_1=0 y Q_2=20/2=10
with q_1 with q_2
150-40*0+3*0=150-20*0+0 150-40*10+3*10^2=150-20*10+10^2
$150=$150 150-400+300 =150-200+100
$50= $ 50
We have two solution if we assume that q=0 like the minimum then the results is $150.
f we assume that q=10 like the minimum then the results is $50.
Google maybe I don't know if that's a soccial media
