Answer
we know that all of these angles sum is 180 so therefore . . .
90 + 39 + 3x = 180
(90+39)=
129 + 3x = 180
(180-129) =
3x = 51
(51/3) =
x = 17
Hope this helps! Have a good day and remember to be tiger fierce!! :)
Answer: The correct answer should be 7.6128
If you do the problem correctly, you will get an answer of 7.6128. This is because there are 4 decimals places in the numbers that are being multiplied. This means that there will be 4 decimal places in the answer. If you have her work, we can find the mistake. It is probably that she counted the wrong number of places.
I believe it is C. X=-1,3,5
Answer: ok ima try my best
the numbers that's in the {} are the umbers you put in for x so
10+10=22 is false
12+10=22 is true
in the x columns you put in the numbers
in the columns with the (x+10=22) you input the number for x so just rewrite it
then you answer if its the answer or not
Step-by-step explanation:
10+10=22 is false
12+10=22 is true < this one is the only one that's true the rest are false
i hope this helps
The image is a bit hard to make out, so I'm going to make some guesses. It looks like it says
![PN=12](https://tex.z-dn.net/?f=PN%3D12)
,
![QP=8](https://tex.z-dn.net/?f=QP%3D8)
, and
![PM=17](https://tex.z-dn.net/?f=PM%3D17)
, and you're asked to find
![QR](https://tex.z-dn.net/?f=QR)
.
You know that
![\Delta NPM](https://tex.z-dn.net/?f=%5CDelta%20NPM)
and
![\Delta NQR](https://tex.z-dn.net/?f=%5CDelta%20NQR)
are similar, which means their corresponding sides are proportional in length. So there's some constant
![c](https://tex.z-dn.net/?f=c)
such that
![NP=cNQ](https://tex.z-dn.net/?f=NP%3DcNQ)
![PM=cQR](https://tex.z-dn.net/?f=PM%3DcQR)
![MN=cRN](https://tex.z-dn.net/?f=MN%3DcRN)
To find
![QR](https://tex.z-dn.net/?f=QR)
, you need to know
![PM](https://tex.z-dn.net/?f=PM)
and the constant
![c](https://tex.z-dn.net/?f=c)
.
Clearly,
![NQ=NP+PQ=12+8=20](https://tex.z-dn.net/?f=NQ%3DNP%2BPQ%3D12%2B8%3D20)
. So, the first equation becomes
![NP=cNQ\iff12=20c\implies c=\dfrac{12}{20}=\dfrac35](https://tex.z-dn.net/?f=NP%3DcNQ%5Ciff12%3D20c%5Cimplies%20c%3D%5Cdfrac%7B12%7D%7B20%7D%3D%5Cdfrac35)
Then in the second equation, you have