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Svetach [21]
3 years ago
9

Answer the questions correctly and i will mark brainliest

Mathematics
2 answers:
kenny6666 [7]3 years ago
7 0
I might be wrong but number 7 is 6 years
dem82 [27]3 years ago
5 0

Answer:

5=31

6=range

7=

Step-by-step explanation:

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What is the geometric mean of 5 and 8?
Lisa [10]

Answer:

About 6.325.

Step-by-step explanation:

The geometric mean between two numbers is the smaller number multiplied by the square root of the quotient of the two numbers. In this case, the square root of 8/5 multiplied by 5 is about 6.325. Hope this helps!

7 0
3 years ago
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6th grade math help me pleaseeee
Ilya [14]

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D :3 -Your friend, Bill Cipher

Step-by-step explanation:

4 0
3 years ago
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Help here ASAP you dont have to write a long one just a short one is fine
pychu [463]

Answer:

Commutative property and associative properties are mixed up.

Step-by-step explanation:

4 0
3 years ago
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A fancy watch was originally priced at $50 but went on sale for 20% off. If Ernesto bought
Viefleur [7K]

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$46

Step-by-step explanation:

4 0
3 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
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