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2 years ago

2. Write the inequality and show all work to solve the

1 answer:

6 0

Yes you are doing it correctly.
$12.00 + $3.00x <= $24.00
$12.00 + $3.00x - $12.00 <= $24.00 - $12.00
$3.00x <= $12.00
$3.00x/$3.00 <= $12.00/$3.00
x <= 4

The number line representation will be an arrow with a shaded round head pointing to the left from tne number 4.

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In the equation, what is the value of s?

Anna35 [415]

Answer:

Step-by-step explanation:

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2 years ago

6/7*(11/18-5/12) pls help: fraction form, please

olasank [31]

Step-by-step explanation:

$\frac{6}{7} \times ( \frac{11}{18} - \frac{5}{12} )$

$\frac{6}{7} \times ( \frac{7}{36} )$

$\frac{42}{252}$

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1 year ago

Nisha and Marcie Drive 20 miles from sisters to hoodoo to go skiing. The speed limit is 75 555 miles per hour. It snowed all nig

slamgirl [31]

If you meant to write this;Nisha and Marcie Drive 20 miles from their sisters to hoodoo to go skiing. The speed limit is 55 miles per hour. It snowed all night, and the safe speed to drive is 40 miles per hour. Explain how you can determine how many more minutes it takes to drive 20 miles at 40 miles per hour in a 55 miles per hour zone.
If you drive 20 miles at 40 mile per hour, then 20 miles divided by 40 miles equals .5.5 times 60 minutes (one hour) is 30 minutesIf you drive 20 miles at 55 mile per hour, then 20 miles divided by 55 miles equals .3636.3636 time 60 minutes (one hour) is 21.8 minutes30 minutes at 40 mph minus 21.8 minutes at 55 mph is 8.2 minutes faster

8 0

3 years ago

(3/5x + 4) + (1/5x -1)

kiruha [24]

Answer:

4/5x+3

Step-by-step explanation:

remove the useless parenthesis, then calculate the x sum then the normal numbers sum

3 0

3 years ago

Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence i

Pavlova-9 [17]

Answer:

$\bar X = \frac{Lower +Upper}{2}$

$\bar X= \frac{1.9+3.3}{2}= 2.6$

And the margin of error with this one:

$\bar X = \frac{Upper-Lower}{2}$

$ME = \frac{3.3-1.9}{2}= 0.7$

Step-by-step explanation:

Assuming that the parameter of interest is the sample mean $\mu$ . And we can estimate this parameter with a confidence interval given by this formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (1.9, 3.3)

Since the confidence interval is symmetrical we can estimate the sample mean with this formula:

$\bar X = \frac{Lower +Upper}{2}$

$\bar X= \frac{1.9+3.3}{2}= 2.6$

And the margin of error with this one:

$\bar X = \frac{Upper-Lower}{2}$

$ME = \frac{3.3-1.9}{2}= 0.7$

7 0

3 years ago