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lisabon 2012 [21]
3 years ago
10

I need help on this for real

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:

x < 3

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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The right triangle below is dilated by a scale factor of 3. Find the perimeter and area
vagabundo [1.1K]

Answers:

For original triangle, perimeter is 60. The area is 120.

The dilated triangle, perimeter is 180. The area is 1080.

Step-by-step explanation:

24 times 3=72

10 times 3=30

26 times 3=78

72+30+78=180

Perimeter of diliated triangle

1/2btimesh=area

1/2 30 times 72=1080 square units

Perimeter of original triangle

24+10+26=60 units

1/2 10 times 24=120 square units

5 0
3 years ago
Yellow Cab Company charges $4 for the first mile plus
kotykmax [81]
4+0.8((11-1)/0.5)=20
$20
7 0
4 years ago
Find the length of the median of each trapezoid.
Step2247 [10]

Answer:

Step-by-step explanation:

3 0
3 years ago
Solve for x.<br><br> 18x−5&lt;−8 or 7x−4≥38
lys-0071 [83]

Answer:

in the first equation: x < -1/6

in the second equation: x≥6

Step-by-step explanation:

just ask!

hope this helps :)

3 0
3 years ago
Super urgent!<br><br> Solve the equation for all real values of x. 3tan^2 = sqrt3 tanx
lutik1710 [3]

f(x) = tan2(x) + (√3 - 1)[tan(x)] - √3 = 0

tan2(x) + √3[tan(x)] - tan(x) - √3 = 0

Factor into

[-1 + tan(x)]*[√3 + tan(x)] = 0

which means

[-1 + tan(x)] = 0 and/or [√3 + tan(x)] = 0

Then

tan(x) = 1

tan-1(1) = pi/4 radians

For the other equation

[√3 + tan(x)] = 0

tan(x) = -√3

tan-1(-√3) = -pi/3

so that

x = pi/4 or -pi/3 in the interval [0, 2pi]

5 0
3 years ago
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