The coterminal angle to (33/10)π on the interval [0, 2π] is (13/10)π
<h3>
How to find the coterminal angle?</h3>
For any given angle A, the family of coterminal angles is defined by:
B = A + n*2π
Where n can be any integer number different than zero.
In this case, we have:
A = (33/10)π
Now we want to get a coterminal angle to A on the interval [0, 2π]. Then we need to find the value of n such that:
B = (33/10)π + n*2π
Is on the wanted interval.
If we take n = -1, then we get:
B = (33/10)π - 2π = (33/10)π - (20/10)π = (13/10)π
Which is in fact in the wanted interval.
The coterminal angle to (33/10)π on the interval [0, 2π] is (13/10)π
If you want to learn more about coterminal angles:
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The answer is D!!!! Hope this helped
Answer:
The answer is D.
Step-by-step explanation:
First, you have to find the area of circle using the formula :
A = π × r²
A = π × 3²
A = 9π
Given that PHU is an equilateral triangle so all sides have a degree of 60°. Next, you have to find the area of minor sector of P and U by using the formula :
A = (θ/360) × π × r²
A = (60/360) × π × 3²
A = 1.5π
Lastly, you have to subtract the area of sector from the area of circle in order to find the area of shaded region :
A = (9π × 2) - (1.5π × 2)
A = 18π - 3π
A = 15π
Answer:
9) 1/42
10) 1/14
Step-by-step explanation:
The probability of the compound event is the product of the probabilities of the parts. Note that the first draw (without replacement) modifies the probability of associated with the second draw.
<h3>9.</h3>
5 is one of 7 tiles. After drawing 5, 6 is one of 6 tiles.
P(5 then 6) = P(5) × P(6 | 5) = 1/7 × 1/6 = 1/42
<h3>10.</h3>
There are 3 odd tiles among the 7. After drawing one of them, 20 is one of 6 tiles.
P(odd then 20) = P(odd) × P(20 | odd) = 3/7 × 1/6 = 3/42 = 1/14
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Alternatively, you can consider the number of permutations of 2 tiles out of 7. That is P(7, 2) = 7!/(7-2)! = 7·6 = 42. Then the trick is to count how many of them will be the sequence of interest.
5 then 6: Among the 42 ways 2 tiles can be drawn, there is only one that is the required sequence: P(5,6) = 1/42.
odd then 20: There are 3 odd numbers, so the possible sequences of interest are (5,20), (7,20), (9,20). That is, there are 3 of 42 sequential draws that match the criteria. P(odd,20) = 3/42 = 1/14.
