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IRINA_888 [86]
3 years ago
7

Find the slope of the line passing through the points (-7, -7) and (-3, 6).

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

13/4 - (13,4) - however your teacher wants you to write it out.

Step-by-step explanation:

Rise (y) over Run (x)

Equation:

y2 - y1

over

x2 - x1

Inputting the numbers, 6 - -7 (aka 6+7) over -3 - -7 (aka -3+7)

6+7 = 13

-3+7 = 4

13/4 - The line is rising moving towards the right.

Hope I helped!

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In 1998, as an advertising campaign, the Nabisco Company announced a "1000 Chips Challenge," claiming that every 18-ounce bag of
Phoenix [80]

Answer:

A 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

Step-by-step explanation:

We are given that statistics students at the Air Force Academy (no kidding) purchased some randomly selected bags of cookies and counted the chocolate chips.

Some of their data are given below; 1219, 1214, 1087, 1200, 1419, 1121, 1325, 1345, 1244, 1258, 1356, 1132, 1191, 1270, 1295, 1135.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                          P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of chocolate chips = \frac{\sum X}{n} = 1238.2

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 94.3

            n = sample of car drivers = 16

            \mu = population mean number of chips in a bag

<em>Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.131 < t_1_5 < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.131) = 0.95

P( -2.131 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.131 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.131 \times {\frac{s}{\sqrt{n} } } , \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ]

                                   = [ 1238.2-2.131 \times {\frac{94.3}{\sqrt{16} } } , 1238.2+2.131 \times {\frac{94.3}{\sqrt{16} } } ]

                                   = [1187.96, 1288.44]

Therefore, a 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

7 0
3 years ago
Divide the sum of 8/7 and-3/14 by their difference
valina [46]

Sum:

8/7+(-3/14)=13/14

difference:

8/7-(-3/14)=19/14

As per given condition we have,

sum/difference=(13/14)/(19/14)=13/19

5 0
3 years ago
Given the table of values below, which equation best represents the information?
Oliga [24]

f(x) = 2x is the Answer!

8 0
3 years ago
Read 2 more answers
*look at the image*<br><br><br> whoever answers will get brainliest
Vanyuwa [196]
It might be 8 hope this helped good luck on ur assignment
5 0
3 years ago
Select the graph which correctly displays the function f(x) = |x + 2|– 3.
Veronika [31]

Answer:

Graph 4

Step-by-step explanation:

I have to put more words lol

5 0
2 years ago
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