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2 years ago

The main goal of a personal budget is to

Mathematics

2 answers:

Sunny_sXe [5.5K]2 years ago

7 0

Answer:

have income be greater than expenses

Step-by-step explanation:

Evgesh-ka [11]2 years ago

3 0

Make sure you don't spend to much and have no more money left

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Plz help I need to know how many bags of snacks they bought in all

spin [16.1K]

Answer:

7x - 2

Step-by-step explanation:

let x be the number of bags of chips, then

3x is the number of bags of pretzels ← 3 times the number of bags of chips

3x - 2 is the number of bags of nachos ← 2 less than bags of pretzels

total snacks bought = x + 3x + 3x - 2 = 7x - 2

6 0

3 years ago

Can someone read this Algebra help please

lilavasa [31]

That means 2*3* the sum of 5+8 which gives you 78 as your answer. Hope this helps and please select as the brainliest answer.

3 0

2 years ago

Read 2 more answers

Which binomials is a factor of 16x^2 + 40xy + 25y^2?

Valentin [98]

Answer: (4x + 5y)^2

Factor the expression.

6 0

2 years ago

HELP someone please!!!! i dont understand

ad-work [718]

Answer:

x = 65.03°

Step-by-step explanation:

To solve for x, we have to apply trigonometric ratio.

Recall: SOH CAH TOA

From the diagram, we know the following:

Reference angle = x

Hypotenuse = 45

Adjacent = 19

Since we know the Hyp and Adj, we would apply CAH, which is:

Cos x = Adj/Hyp

Plug in the values

$cos(x) = \frac{19}{45}$

$x = cos^{-}(\frac{19}{45})$

x = 65.0250346°

x = 65.03° (nearest hundredth)

4 0

2 years ago

Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh

yuradex [85]

Answer:

The northern lighthouse is approximately $24.4\; \rm mi$ closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as $\rm N$ , the southern lighthouse as $\rm S$ , and the boat as $\rm B$ . These three points would form a triangle.

It is given that two of the angles of this triangle measure $40^{\circ}$ (northern lighthouse, $\angle {\rm N}$ ) and $21^{\circ}$ (southern lighthouse $\angle {\rm S}$ ), respectively. The three angles of any triangle add up to $180^{\circ}$ . Therefore, the third angle of this triangle would measure $180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ}$ (boat $\angle {\rm B}$ .)

It is also given that the length between the two lighthouses (length of $\rm NS$ ) is $75\; \rm mi$ .

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, $\angle {\rm B}$ is opposite to side $\rm NS$ , whereas $\angle {\rm S}$ is opposite to side ${\rm NB}$ . Therefore:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}$ .

Substitute in the known measurements:

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}$ .

Rearrange and solve for the length of $\rm NB$ :

$\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}$ .

(Round to at least one more decimal places than the values in the choices.)

Likewise, with $\angle {\rm N}$ is opposite to side ${\rm SB}$ , the following would also hold:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}$ .

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}$ .

$\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}$ .

In other words, the distance between the northern lighthouse and the boat is approximately $30.73\; \rm mi$ , whereas the distance between the southern lighthouse and the boat is approximately $55.12\; \rm mi$ . Hence the conclusion.

4 0

2 years ago