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schepotkina [342]
4 years ago
10

The scatterplot shows gym membership (in thousands) for 26 different gyms in 1995 and 2005. Which labeled point represents the g

ym that had the smallest percent increase in gym membership from 1995 to 2005?

Mathematics
2 answers:
nirvana33 [79]4 years ago
8 0

thx the answer is c i hope it helps

Brut [27]4 years ago
4 0
I found the plot online and attached for clarity.
To get percentage increase we can use the following formula:
\Delta\%= \frac{N_{05}-N_{95}}{N_{95}}
Here is the table with all the information needed to find the answer.
\begin{tabular}{llll}
Gym & N 2005 & N 1995 & Percentage increase \\
A   & 1      & 0.5    & 100                 \\
B   & 1.20   & 1      & 20                  \\
C   & 4      & 2      & 100                 \\
D   & 4.5    & 3      & 50                  \\
E   & 5      & 4      & 25                 
\end{tabular}

We can see from the table that gym B had the smallest percent increase for 1995 to 2005.

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For each of the following research scenarios, decide whether the design uses a related sample. If the design uses a related samp
Wewaii [24]

Answer:1. uses a related sample - repeated measures

2. . does not use a related sample--a

Step-by-step explanation:

Question 1.

step1  A repeated measure design is a design which measures a given sample repeatedly over a given time using different conditions or related measures.

step 2:In the treatment for compulsive hoarding, Here, measures are taken two times ie before and after treatment on the same 50 hoarders which shows a repeated measure, also the design is a within related sample of the same 50 hoarders to give measurement at different conditions  of treatment for  high and low hoarding scores so the design describes  a related sample - repeated measures

Question 2:

step 1 ; An unrelated sample  occurs when Samples being measured do not depend on each other  

Step 2;  1st Sample for comparison by John are random lonely people  and Second Sample are random non lonely people. so the two samples are independent on each other and will give different  measurement based on quality of sleep.   So the design does not use a related sample

8 0
3 years ago
a hotel has a number of meeting rooms,m, available for events. each meeting room has 325 chairs. write an equation to represent
liq [111]
C=325m
Because for every meeting room there is 325 chairs and c=the total of chairs
6 0
4 years ago
Which is the rate of change for the interval between 3 and 6 on the x-axis?
Anna71 [15]

Answer:

The correct answer is 2.

Step-by-step explanation:

To find this, first identify the ordered pairs at those two points. They would be (3, -2) and (6, 4). Then use the slope formula with those two points to find the rate of change.

m(slope) = (y2 - y1)/(x2 - x1)

m = (4 - - 2)/(6 - 3)

m = 6/3

m = 2

8 0
3 years ago
Read 2 more answers
Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim
tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{10959}{25} =438.36

Sum of squares of differences = 175413.76

S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49

Population mean, μ = 425 mg/L

Sample mean, \bar{x} = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813

Now, t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108

Since,                        

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0
3 years ago
Pls give me a real awnser this is a chart so the question is the pic
Airida [17]

Answer:

The answer is in the attachment!

Step-by-step explanation:

8 0
3 years ago
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