Answer:
D) 1980 to 2000
Step-by-step explanation:
Finding the average rate of change in each interval to determine the greatest one.
Production per interval
1950-1960 =
= 10 million
1960-1970 =
= 20 million
1970-1980 =
= 30 million
1980-2000 =
million
Rate of change (1950-1960)= 
Rate of change (1960-1970) = 
Rate of change (1970-1980)= 
Rate of change (1980-2000)= 
∴ rate of change between 1980 to 2000 is 126.78%
Answer:
See picture attached below.
Step-by-step explanation:
To graph the system, graph each line separately.
y = 3x + 3 ha slope 3 and y-intercept 3.
Start at 3 on the y-axis and mark a point. Then from this point move up 3 units and to the right 1 unit. Mark a point and connect.
y=-x - 3 has slope -1 and y-intercept -3.
Start at -3 on the y-axis and mark a point. Then from this point move down 1 unit and to the right 1 unit. Mark a point and connect.
This graph is represented in the picture attached.
Answer:
Step-by-step explanation:
Remark
This is a cosine law problem.
a = 12
b = 15
C = 83
Notice that the angle is enclosed by 2 given sides. That's what a cosine problem looks like (one of the two choices.
Formula
c^2 = a^2 + b^2 - 2ab*cos(C)
Solution
c^2 = 12^2 + 15^2 - 2*12*15 * cos(83)
c^2 = 144 + 225 - 360 * cos(83)
cos(83) = 0.1219
c^2 = 144 + 225 - 360 * 0.1219
c^2 = 369 - 43.884
c^2 = 325.116
sqrt(c^2) = sqrt(325.116)
c = 18.031
To the nearest tenth, the answer is 18.0 and you must include the 0.