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kirill115 [55]
4 years ago
11

A local grocery store is giving out

Mathematics
1 answer:
Marat540 [252]4 years ago
3 0

Answer:

The original price range of soda is $10 to $39.4

Step-by-step explanation:

Given as :

The discount coupon applied on grocery = 5%

The cost of soda after discount coupon ranges = $0.50 to $1.97

Let the original price range of soda = $A

Now, According to question

discount on original price = the cost after discount

So, initial original price = x

5% of x = $0.50

0.05 × x = $0.50

∴ x = \dfrac{0.50}{0.05}

i.e x = $10

Again final original price = y

5% of y = $1.97

0.05 × y = $1.97

∴ y = \dfrac{1.97}{0.05}

i.e y = $39.4

So, The original price range of soda = $A = $10 to $39.4

Hence, The original price range of soda is $10 to $39.4  Answer

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Solve each equation using the quadratic formula. Find the exact solution, then approximate the solution to the nearest hundredth
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Answer:

n_1=2.72\\n_2=0.61


Step-by-step explanation:

 To solve this problem you  must apply the proccedure shown below:

1. You have that the quadratic formula is:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. To solve the quadratic equation you must substitute the values. So, you have that:

a=3\\b=-10\\c=5

Then you have:

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3. Therefore, you obtain the following result:

x_1=2.72\\x_2=0.61



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Answer:

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