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marusya05 [52]
3 years ago
10

Last year, Keith opened an investment account with $8200. At the end of the year, the amount in the account had decreased by 7.5

%. How much is this decrease in dollars? How much money was in his account at the end of last year?
Mathematics
1 answer:
Alona [7]3 years ago
8 0

Answer:

You would multiply $8200 by .075, giving you 615. Then to find the decrease. Take the starting value (8200) by the end value (615). and you would get 7,585.

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A)<br>be<br>85°<br>120°<br>(2x - 10°<br>X​
Lunna [17]

Let's see what to do buddy...

_________________________________

Step (1)

We know that the sum of the interior angles of any n-sided figure is obtained from the following equation :

(n - 2) \times 180

Our figure has 5 sides ;

So , sume the interior angles of it equals :

(5 - 2) \times 180 = 3 \times 180 = 540 \\

_________________________________

Step (2)

First look at the photo which I post.

According it we have :

(180 - x) + 120 + 85 + (2x - 10) + 90 = 540 \\

2x - x + 475 - 10 = 540

x + 465 = 540

Subtract the sides of the equation minus 465 :

x = 540 - 465

x = 75

_________________________________

And we're done.

Thanks for watching buddy good luck.

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3 0
3 years ago
12.12.12.12 +7(3.3.3.3+3)<br> What the answer
Black_prince [1.1K]

Answer:

23.253528

Your welcome

4 0
3 years ago
What is the constant in the equation y=2.7x​
kirill [66]

Answer:

The constant is 2.7. This number never changes.

5 0
4 years ago
What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t
weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

A=LW

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

L=BC\\W=AB

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the points

A(2,-1),B(5,2),C(12,-5),D(9,-8)

<em>Find out the distance BC</em>

we have

B(5,2),C(12,-5)

substitute in the formula

d=\sqrt{(-5-2)^{2}+(12-5)^{2}}

d=\sqrt{(-7)^{2}+(7)^{2}}

d_B_C=\sqrt{98}\ units

<em>Find out the distance AB</em>

we have

A(2,-1),B(5,2)

substitute in the formula

d=\sqrt{(2+1)^{2}+(5-2)^{2}}

d=\sqrt{(3)^{2}+(3)^{2}}

d_A_B=\sqrt{18}\ units

<em>Find out the area</em>

A=(L)(W)

we have

L=d_B_C=\sqrt{98}\ units

W=d_A_B=\sqrt{18}\ units

substitute

A=(\sqrt{98})(\sqrt{18})=42.0\ units^2

4 0
4 years ago
Can someone solve ASAP
WINSTONCH [101]

Answer:

18.5 in=decimal feet,

Step-by-step explanation:

1)18.5/12=18.512

2)18.512=1.542 feet

5 0
3 years ago
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