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notka56 [123]
3 years ago
6

Solve the system using elimination.

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0
1.)  6x=12
x=2
3(2)+3y=-9
6+3y=-9
3y=-3
y=-1
(2,-1)

2.) 7x=-35
x=-5
5x+2y=-19
5(-5)+2y=-19
-25+2y=-19
2y=-44
y=-22
(-5,-22)

3.) 4x=-16
x=-4
2(-4) +3y=1
-8+3y=1
3y=-7
y=-7/3
(-4,7/3)

4.)7x=35
x=5
2(5)+3y=-5
10+3y=-5
3y=5
y=5/3
(5,5/3)

5.) 2x=-8
x=-4

x+4y=4
-4+4y=4
4y=0
y=1
(-4,1)


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See Explanation

Step-by-step explanation:

Your question is incomplete, as the equations or graph or table(s) were not given.

However, I'll give a general way of solving this.

Take for instance, the equations are:

y = \frac{4}{3}x - 1

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To do this, we start by equating both equations.

y = y

i.e.

\frac{4}{3}x - 1= \frac{2}{3}x - \frac{1}{2}

Collect Like Terms

\frac{4}{3}x - \frac{2}{3}x= 1 - \frac{1}{2}

Take LCM

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Cross Multiply

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4x = 3

Make x the subject

x = \frac{3}{4}

Substitute 3/4 for x in y = \frac{4}{3}x - 1

y = \frac{4}{3} * \frac{3}{4} - 1

y = 1 - 1

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Step-by-step explanation:

When using the distributive property, 6(2x + 4) becomes 12x + 24

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