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4 years ago

Solve the system using elimination.

1 answer:

riadik2000 [5.3K]4 years ago

7 0

1.) 6x=12
x=2
3(2)+3y=-9
6+3y=-9
3y=-3
y=-1
(2,-1)

2.) 7x=-35
x=-5
5x+2y=-19
5(-5)+2y=-19
-25+2y=-19
2y=-44
y=-22
(-5,-22)

3.) 4x=-16
x=-4
2(-4) +3y=1
-8+3y=1
3y=-7
y=-7/3
(-4,7/3)

4.)7x=35
x=5
2(5)+3y=-5
10+3y=-5
3y=5
y=5/3
(5,5/3)

5.) 2x=-8
x=-4

x+4y=4
-4+4y=4
4y=0
y=1
(-4,1)

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Someone please help!!

rewona [7]

Answer:

Option 2: (1,0) is the correct answer

Step-by-step explanation:

Given inequality is:

y>-5x+3

In order to find which point is solution to the given inequality we'll put the point one by one in the inequality. If the point satisfies the inequality, then the point is the solution of the inequality.

Putting (0,3) in inequality

$3 > -5(0)+3\\3>0+3\\3>3$

Putting (1,0) in inequality

$0>-5(1)+3\\0>-5+3\\0>-2$

Putting (-3,1) in inequality

$1 > -5(-3)+1\\1> 15+1\\1>16$

Putting (-1,-2) in inequality

$-2>-5(-1)+3\\-2>5+3\\-2>8$

The inequality is true for (1,0)

Hence,

Option 2: (1,0) is the correct answer

4 0

3 years ago

For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec

telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

$4sin(x^2) = 0$

$sin(x^2) = 0$

$x^2 = n\pi$ where n = 0, 1, 2,3, 4, 5,...

$x = \sqrt(n\pi)$

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

$f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0$

$xcos(x^2) = 0$

$x = 0$ or

$cos(x^2) = 0$

$x^2 = \frac{\pi}{2} + n\pi$ where n = 0, 1, 2, 3

$x = \sqrt{\pi(n+1/2)}$

Since we are restricting x between 0 and 3 we can stop at n = 2

So our critical points are at

x = 1.25, $y = f(1.25) = 4sin(1.25^2) = 4$

x = 2.17 , $y = f(2.17) = 4sin(2.17^2) = -4$

x = 2.8, $y = f(2.8) = 4sin(2.8^2) = 4$

For the inflection point, we can take the 2nd derivative and set it to 0

$f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0$

$cos(x^2) = 2x^2sin(x^2)$

$tan(x^2) = \frac{1}{2x^2}$

We can solve this numerically to get the inflection points are at

x = 0.81, $y = f(0.81) = 4sin(0.81^2) = 2.44$

x = 1.81, $y = f(1.81) = 4sin(1.81^2) = -0.54$

x = 2.52, $y = f(2.52) = 4sin(2.52^2) = 0.27$

3 0

3 years ago

Aaron bought a set of plastic ice cubes with a mixture of water and air inside.

LekaFEV [45]

Answer:

Volume of water and air is 3,000 mm³

Step-by-step explanation:

Given:

Length of base = 15 mm

Width of base = 20 mm

Height of figure = 30 mm

Find:

Volume of water and air is inside each of the plastic ice cubes.

Computation:

Height of each rectangular pyramid = Height of figure / 2

Height of each rectangular pyramid = 30 / 2

Height of each rectangular pyramid = 15 mm

Volume of each rectangular pyramid = lbh / 3

Volume of each rectangular pyramid = [15 × 20 × 15] / 3

Volume of each rectangular pyramid = [4,500] / 3

Volume of each rectangular pyramid = 1,500 mm³

Volume of water and air is inside each of the plastic ice cubes = 2 × Volume of each rectangular pyramid

Volume of water and air is inside each of the plastic ice cubes = 2 × 1,500

Volume of water and air is inside each of the plastic ice cubes = 3,000 mm³

6 0

4 years ago

Given that [Image Display]

givi [52]

Answer:

The answer is option D.

All real numbers including zero

Hope this helps

3 0

3 years ago

Read 2 more answers

In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t

Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

5 0

3 years ago

Read 2 more answers