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3 years ago

I need help with, this. Select all that apply. thanks

Mathematics

1 answer:

Ymorist [56]3 years ago

3 0

Answer: a e f

Step-by-step explanation:

A: 2(0)+3(2)= 0+6=6

B: 2(0)+3(6)=0+18= 18

C: 2(2)+3(3)=4+9=13

D: 2(3)+3(-2)=6+(-6)=0

E: 2(3)+3(0)=6+0=6

F: 2(6)+3(-2)=12+(-6)=6

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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

For the trinomial x2 + 10x + 21, we want to find two binomial factors

ratelena [41]

X^2 + 10X + 21

(X + 3)(X + 7)

7 0

4 years ago

Which of the following equations represents a line parallel to the line given by y=5x +9?

erma4kov [3.2K]

Answer:

y = 5x + 1

Step-by-step explanation:

Lines that are parallel to each other on a graph would have the same slope but different y-intercepts. When option A's equation is graphed along with the line given in the question, the lines appear to be parallel.

Option A should be the correct answer.

7 0

4 years ago

PLS HELP FAST I NEED IT

Gemiola [76]

Answer:

(b) 1:9

Step-by-step explanation:

(b) x*y : kx*ky, so 1:k² with k=3 is 1:9

(c) Assuming the rectangles get a z dimension, the volumes would have a ratio of xyz : xkykzk = xyz : xyzk³ = 1 : k³. With k=2 that is 1:8. But the z was never introduced so this is a bit inconclusive.

3 0

3 years ago

Please help I am desperate

Phoenix [80]

Answer:

see below

Step-by-step explanation:

72pi cubic inches

1/3 pi r ^2 * h = 72 pi

1/3 r^2 h = 72

You can theoretically find infinite answers to this and get enough points for the semester where you don't have to do work anymore. I will list a couple more possible answers below

r = radius, h = height

r = 2, h = 54

r = 3, h = 24

r = 4, h = 27/2

r = √(1/pi), h = 72pi

5 0

3 years ago