A: (-4,1), B(1,-3), C(0,2), D(5,0), E(-3,6) F(-4,-5), G(0,-4), H(2,4) I(-2,3), J(5,-2)
Quadrant 1: D, H
Quadrant 2: A, I, E
Quadrant 3: F
Quadrant 4: B, J
on the x axis: D
On the y axis: G, C

8 0

2 years ago

For a right triangle ABC, you are told that cos A = x and sin A = y. Which option below gives an expression that is equivalent t

loris [4]

Answer:

Step-by-step explanation:

We know that

cos A = adjacent / hypotenuse

sin A = opposite / hypotenuse

Therefore, sin A / cos A =

(opposite / hypotenuse) / (adjacent / hypotenuse)

= (opposite/hypotenuse) * (hypotenuse / adjacent)

= opposite / adjacent

= tan A

Therefore, tan A = sin A / cos A = y/x

8 0

3 years ago

The time t required to empty a tank varies inversely as

vesna_86 [32]

If $t$ and $r$ are inverse proportional to one another, then for some constant volume $V$ we have

$V = tr$

It takes 45 min to empty a tank containing at 300 gal/min, so the tank contains

$V = (45\,\mathrm{min}) \left(300\dfrac{\rm gal}{\rm min}\right) = 13500\,\mathrm{gal}$

of liquid.

If it's emptied at 500 gal/min, it would take

$13500\,\mathrm{gal} = t \left(500\dfrac{\rm gal}{\rm min}\right) \implies t = \boxed{27\,\mathrm{min}}$

4 0

2 years ago