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Zolol [24]
3 years ago
6

The last time Alejandro's height was measured he was 61.5 inches tall. He was measured again today and is now 68.7 inches tall.

How much did he grow? Write an expression. Use g to represent the number of inches Alejandro grew.
Mathematics
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

He grew 7.2 inches.

Step-by-step explanation:

68.7-61.5=7.2

Expression:

68.7-61.5=g

or

61.5+g=68.7

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A 2-column table with 5 rows. The first column is labeled x with entries negative 4, negative 1, 0, 2, 3. The second column is l
Elenna [48]

Answer:

f(x)= 1.8x + 1

Step-by-step explanation:

Just got it right on edge :)

7 0
3 years ago
Triangle A C F is shown. Lines are drawn from each point to the opposite side and intersect at point D. Line segments A E, F B,
Aneli [31]

Answer:

No, the ratio between AD and DE is 3:1.

Step-by-step explanation:

I took the test already.

7 0
2 years ago
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Solve (x - 5)2 = 3.<br> A. x = 5 + 1/3<br> B. X=-5313<br> C. x = 8 and x = -2<br> D. X = 3 + -15
Luden [163]

Answer:

none of the above, x=13/2

Step-by-step explanation:

(x-5)2= 3

2x_10=3

2x=13

x=13/2

5 0
3 years ago
2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0
3 years ago
Read 2 more answers
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Mkey [24]

For this case, we have to:

By definition, we know:

The domain of f (x) = \sqrt [3] {x} is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.

So, we have:

y = \sqrt [3] {x-2} withx = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x+2}with x = 0:\ y = \sqrt [3] {2} is also defined.

f (x) = \sqrt {x}has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative whenx = 0.

While y = \sqrt {x+2} if it is defined for x = 0.

Answer:

y = \sqrt {x-2}

Option b

6 0
3 years ago
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