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Zolol [24]
2 years ago
6

The last time Alejandro's height was measured he was 61.5 inches tall. He was measured again today and is now 68.7 inches tall.

How much did he grow? Write an expression. Use g to represent the number of inches Alejandro grew.
Mathematics
1 answer:
stiv31 [10]2 years ago
6 0

Answer:

He grew 7.2 inches.

Step-by-step explanation:

68.7-61.5=7.2

Expression:

68.7-61.5=g

or

61.5+g=68.7

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Kaitlin, Tony, and Austin sent a total of 103 text messages over their cell phones during the weekend. Austin sent 4 times as ma
emmainna [20.7K]

The number of messages Kaitlyn, Tony and Austin sent are 13, 18 and 72 messages respectively.

<h3>How to write and solve equation?</h3>

let

  • Number of messages Kaitlyn sent = x
  • Number of messages Tony sent = x + 5
  • Number of messages Austin sent = 4(x + 5)
  • Total messages = 103

103 = x + (x + 5) + 4(x + 5)

103 = x + x + 5 + 4x + 20

103 = 6x + 25

103 - 25 = 6x

78 = 6x

x = 78/6

x = 13

Number of messages each sent:

Number of messages Kaitlyn sent = x

= 13 messages

Number of messages Tony sent = x + 5

= 13 + 5

= 18 messages

Number of messages Austin sent = 4(x + 5)

= 4(13 + 5)

= 4(18)

= 72 messages

Learn more about equation:

brainly.com/question/2972832

#SPJ1

3 0
1 year ago
Please help me thanks
PilotLPTM [1.2K]
6x + 45 + 3x = 180
9x - 45 = 180
9x = 135
x = 15
8 0
2 years ago
Sketch the graph of each line
sveta [45]
Use Desmos it helps you with questions like that

3 0
2 years ago
Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
2 years ago
The school need to make $750 in order to cover all of their expenses.They estimate 200 students will come to the dance.If they m
densk [106]

9514 1404 393

Answer:

  $3

Step-by-step explanation:

The cost that hasn't been covered by bake sale proceeds is ...

  $750 -150 = $600

If that cost is divided among 200 students, the amount each student needs to pay is ...

  $600/(200 students) = $3/student

They need to charge $3 per ticket.

8 0
2 years ago
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