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3 years ago

Solve for x. −1/2(x 2) 1 1/2x=3

Mathematics

1 answer:

AlekseyPX3 years ago

4 0

-1/2(x + 2) + 1 + 1/2 x = 3
-1/2 x - 1 + 1 + 1/2 x = 3
0 = 3

x has no solution.

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A boy has in his pocket a 50-cent piece, two dimes and two pennies. If he pulls out a coin at random, what is the probability it

rodikova [14]

Well, from what I can tell he has 1 50 cent piece, 2 Dimes, and 2 Pennies. Meaning 5 objects in total, considering that it asks for "at least ten cents" that would mean the 2 Dimes and the 1 50 cent piece.
Since that is 3 objects out of the 5, being 3/5ths, that would mean he has a 60% chance or probability for the first draw.

Hopefully that helps. ^ ^
{-Ghostgate-}

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2 years ago

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Jk=8x+6 and kL=6x+20<br> Find JL

mr Goodwill [35]

Jk=8x+6
J=(8x+6)/k

kL=6x+20
L=(6x+20)/k

JL=(8x+6)/k * (6x+20)/k
=(48x²+196x+120)/k²

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3 years ago

Every month Tanesha pays a fixed fee of $10 to use the parking lot at her workplace. She must also pays $2 each day that she par

Gnom [1K]

10 + 2x • the amount of days in the month

4 0

3 years ago

The growth of a city is described by the population functionwhereis the initial population of the city, t is the time in years,

mamaluj [8]

Complete question:

The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at

Answer:

27,800

Step-by-step explanation:

We need to obtain the initial population(P0) and constant value (k)

Population function : p(t) = P0e^kt

At t = 0, population = 19,000

19,000 = P0e^(k*0)

19,000 = P0 * e^0

19000 = P0 * 1

19000 = P0

Hence, initial population = 19,000

At t = 3; population = 23,000

23,000 = 19000e^(k*3)

23000 = 19000 * e^3k

e^3k = 23000/ 19000

e^3k = 1.2105263

Take the ln

3k = ln(1.2105263)

k = 0.1910552 / 3

k = 0.0636850

At t = 6

p(t) = P0e^kt

p(6) = 19000 * e^(0.0636850 * 6)

P(6) = 19000 * e^0.3821104

P(6) = 19000 * 1.4653739

P(6) = 27842.104

27,800 ( nearest whole number)

3 0

3 years ago

Write a polynomial function of least degree with the given zero. -1+ √ 2, √ 3

kirill115 [55]

Answer:

f(x) = $x^{4}$ + 2x³ - 4x² - 6x + 3

Step-by-step explanation:

Note that radical zeros occur in conjugate pairs, thus

- 1 + $\sqrt{2}$ is a zero then - 1 - $\sqrt{2}$ is also a zero

$\sqrt{3}$ is a zero then - $\sqrt{3}$ is also a zero

Thus the corresponding factors are

(x - (- 1 + $\sqrt{2}$ ) ), (x - (- 1 - $\sqrt{2}$ ) ), (x - $\sqrt{3}$ ), (x - (- $\sqrt{3}$ )), that is

(x + 1 - $\sqrt{2}$ ), (x + 1 + $\sqrt{2}$ ), (x - $\sqrt{3}$ ), (x + $\sqrt{3}$ )

The polynomial is then the product of the roots

f(x) = (x + 1 - $\sqrt{2}$ )(x + 1 + $\sqrt{2}$ )(x - $\sqrt{3}$ )(x + $\sqrt{3}$ )

= ((x + 1)² - ( $\sqrt{2}$ )²)((x² - ( $\sqrt{3}$ )²)

= (x² + 2x + 1 - 2)(x² - 3)

= (x² + 2x - 1)(x² - 3) ← distribute

= $x^{4}$ - 3x² + 2x³ - 6x - x² + 3

= $x^{4}$ + 2x³ - 4x² - 6x + 3

6 0

3 years ago