Answer:
I hate that clfufjwwjdkfkrifjeidoqodjfrjkejakxkdk
Step-by-step explanation:
Answer:
about $0.14
Step-by-step explanation:
$4.36 (1/32) =
0.13625 =
about $0.14
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer:
a5 =243 x (1/3)^(5-1) = 243x 1/81 =3
Explanation
a(n) = a(1) x r^(n-1)
Total length of the fabric is 
We need to find the number of scarves can she make if she needs 5/6 of a yard for each scarf.
Let she needs x scarves. So, ATQ
Hence, she can make 8 scarves.