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2 years ago

Need help please help me

Mathematics

1 answer:

Viefleur [7K]2 years ago

4 0

Answer:

k/3 + 6 < 7 = k< 3

2 + p/2 ≥ 7 = p ≥ 10

5 − 4n < 8 − 5n = n < 3

−3n −4 > 4n + 10 = n < -2

9w − 4w + 6 ≥1 + 5w = I couldn't get a solution for this one sorry

Step-by-step explanation:

Hope this helps

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Which expression is equivalent to...

torisob [31]

Answer:

$x^{\frac{2}{7} } y^{-\frac{3}{5} } \\$ i.e answer A.

Step-by-step explanation:

This question involves knowing the following power/exponent rule:

$\sqrt[n]{x^m} = x^\frac{m}{n} \\\\so \sqrt[7]{x^2} = x^\frac{2}{7} \\\\and \\\\ \sqrt[5]{y^3} = y^\frac{3}{5} \\$

Next, when a power is on the bottom of a fraction, if we want to move it to the top, this makes the power become negative.

so the y-term, when moved to the top of the fraction, becomes:

$y^{-\frac{3}{5} } \\$

So the answer is: $x^{\frac{2}{7} } y^{-\frac{3}{5} } \\$

7 0

3 years ago

07.03 MC) An equation is shown below: 9(3x – 16) + 15 = 6x – 24 Part A: Write the steps you will use to solve the equation, and

VARVARA [1.3K]

Answer:

x=5

Step-by-step explanation:

Alright you will need to use PEMDAS for this

Parenthesis
Exponent
Multiplication
Division
Addition
Subtraction ( Take note of this )

Step 1

9(3x – 16) + 15 = 6x – 24 You will remove parenthesis here

27x-129=6x-24

Step 2

Then subtract 6x,

27x-129=6x-24

21x-129=-24

Step 3

Then you add 129 to the sides,

21x-129=-24

21x=105

After that, you divide the sides by 21 so that you can get your answer

So therefore, your answer will be x=5

6 0

3 years ago

Read 2 more answers

Answer with A B C D. Correct answer gets brainlest.

oksian1 [2.3K]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the slope of a line that passes through the points (-8, 14) and (4,-4)?

Simora [160]

Answer:

the answer is -3/2

Step-by-step explanation:

Trust me its correct

pls mark me as brainliest

4 0

2 years ago

Find dy/dx if y =x^3+5x+2/x²-1

stiks02 [169]

<u>Differentiate using the Quotient Rule</u> –

$\qquad$ $\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\$

According to the given question, we have –

f(x) = x^3+5x+2
g(x) = x^2-1

Let's solve it!

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\$

$\qquad$ $\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\$

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\$

$\qquad$ $\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\$

7 0

2 years ago