Find minutes per mile by dividing time by distance:
45 minutes / 6 miles = 7.5 minutes per mile
Now multiply his speed by each distance:
7.5 x 9 = 67.5 minutes
7.5 x 15 = 112.5 minutes
Now subtract the two:
112.5 - 67.5 = 45 minutes more
Answer:
Step-by-step explanation:
When Riko left his house, Yuto was 5.25 miles along the path.
Average speed of Riko = 0.35 miles per minute
Average speed of Yuto = 0.25 miles per minute
First we will calculate the time in which Riko will catch Yuto on the track.
Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto
= 0.35 - 0.25
= 0.10 miles per minute
Now we this relative velocity tells that Riko is moving and Yuto is in static position.
By the formula,
Average speed = 
0.10 = 
t = 
t = 52.5 minutes
Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.
So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5
Here time can not be less than zero because time can not be with negative notation. It will always start from 0.
The answer is 20.
5*10-5*6=50-30=20
First of all we know the
Absolute Value Function that is:

This is called the
Parent Function <em>of the Absolute Value Function.</em>
From the equation:

The term:

means that the the Parent Function is <em>shifted</em>
two units <em>to the left</em>.
On the other hand, the term:

means that the function

is <em>shifted</em>
three units <em>downward. </em>So the result is the graph shown below
The answer to your question is D. 512