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OlgaM077 [116]
3 years ago
15

Write the following inequality in slope intercept form -12x - 2y is greater than or equal to -42

Mathematics
2 answers:
Radda [10]3 years ago
7 0

Answer:

y ≤ -6x + 21 is the inequality.

Step-by-step explanation:

A slope intercept form of a line is represented as y = mx + c

where m = slope of the line

and c = y intercept

The given inequality is -12x - 2y ≥ -42

Now we divide the inequality by 2

\frac{(-12x-2y)}{2}\geq  \frac{-42}{2}

-6x - y ≥ -21

Now we add y on both the sides of the inequality

-6x - y + y ≥ -21 + y

-6x ≥ y - 21

We add 21 on both the sides of the inequality

-6x + 21 ≥ y - 21 + 21

-6x + 21 ≥ y

Or y ≤ -6x + 21

tino4ka555 [31]3 years ago
5 0

First of all, we write the requested inequality:

-12x-2y\geq -42

The slope-intercept form of a line is y=mx+q, so we basically have to solve the inequality for y: we move the -12x term to the right:

-2y\geq 12x-42

And we divide both sides by -2. Note that, since -2 is negative, this division also inverts the inequality sign:

y \leq -6x+21

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Westkost [7]

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\dfrac{1}{2x(x-1)}

Step-by-step explanation:

Given

\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)

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x^2+2x+1=(x+1)^2

Consider the denominator:

x^2-1=(x-1)(x+1)

Hence, the fraction becomes

\dfrac{(x+1)^2}{(x-1)(x+1)}=\dfrac{x+1}{x-1}

Consider the expression in brackets:

2x^2+2x=2x(x+1)

Divide:

\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)=\dfrac{x+1}{x-1}\div 2x(x+1)=\dfrac{x+1}{x-1}\times \dfrac{1}{2x(x+1)}=\dfrac{1}{2x(x-1)}

4 0
3 years ago
Log3+logx=5/2<br>find x​
Naya [18.7K]

Answer:

x = 105.4

Step-by-step explanation:

We are given;

Log 3 + log x = 5/2

We are required to find x;

We are going to use the laws of logarithms to solve for x

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log a + lob b = log(ab)

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we get;

log 3x = 2.5

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Given, logₐb= x , then b = a^x

In this case;

log 3x = 2.5

we get , 3x = 10^2.5

That is , 3 x = 316.227

                x = 105.4

Thus, the value of x is 105.4

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3 years ago
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