Simultaneous equations
Jamar=J
Josh=j
4J=j
20+J=2j
Then
4J=j
-4 (J)=-4(2j-20)
So
0=-7j+80
7j=80
j=80÷7
Answer:
w = 3
Step-by-step explanation:
19w - 1 = 11w + 23
19w - 11w = 23 + 1
8w = 24
w = 3
<h3>17 heavy equipment operators and 14 general labourers were employed</h3>
<em><u>Solution:</u></em>
Let x = number of heavy equipment operators employed
Then,
31 - x = number of laborers employed
From given,
Pay of heavy equipment operators = $ 138 per day
Pay of general labours = $ 93 per day
Payroll was $3648
Therefore,
number of heavy equipment operators x Pay of heavy equipment operators + number of laborers employed x Pay of general labours = 3648
138x + 93(31 - x) = 3648
138x + 2883 - 93x = 3648
45x = 3648 - 2883
45x = 765
x = 17
Thus,
31 - x = 31 - 17 = 14
Therefore, 17 heavy equipment operators and 14 general labourers were employed
The constant is a number by itself.....no variables
so the constant in y = 4x - 110 is : -110
