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3 years ago

Look at the following numbers:

Mathematics

2 answers:

NISA [10]3 years ago

7 0

5 + ( -5) = 0

So the answer pair of numbers would be 5 and -5

Ivahew [28]3 years ago

7 0

Answer:

-5 + 5

Step-by-step explanation:

-5 + 5 = 0

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Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States. In Australia, only 1.5% of

Umnica [9.8K]

Answer:

a. X is a binomial random variable with n = 50 and p = 0.04

b. Y is a binomial random variable with n = 40 and p = 0.015

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

X: the number of US residents (out of 50) with blood type AB.

Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States

This means that $p = 0.04, n = 50$

Y: the number of Australians (out of 40) with blood type AB.

In Australia, only 1.5% of the population has blood type AB.

This means that $p = 0.015, n = 40$

Z: the total number of individuals (out of 90) with blood type AB.

Here

$n = 90, p = 0.04*\frac{50}{90} + 0.015*\frac{40}{90} = 0.0289$

Which of the following is true about the random variables X, Y, and Z?

Options a and b are true, while c is false.

7 0

3 years ago

"how many different rectangles" can you draw that have a perimeter of 12, 14

amm1812

Perimeter of rectangle = length + length + width + width

To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14

Rectangle with perimeter 12

Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3

Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have

Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have

The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12

length = 4 and width = 2
length = 5 and width = 1
--------------------------------------------------------------------------------------------------------------

Rectangle with perimeter of 14

Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14

Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14

Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14

We can have 3 different combinations of length and width

3 0

3 years ago

Solve the inequality –3(r – 5) + 7 > 28.

docker41 [41]

Answer: r<-2

Step-by-step explanation:

-3(r-5)+7>28

-3(r-5)+7-7>28-7

-3(r-5)>21

3(r-5)/3 < -21/3

r-5<-7

r-5+5<-7+5

r<-2

5 0

3 years ago

1. Identify a pair of alternate exterior angles.

KonstantinChe [14]

Answer:

d. ∠2 and ∠6

Step-by-step explanation:

Definition : Alternate Exterior Angles are a pair of angles on the outer side of each of those two parallel lines but on opposite sides of the transversal.

Option a. ∠3 and∠4

These angles are interior angles.

Option b . ∠1 and∠2

These angles are linear pair.

Option c . ∠1 and ∠6

These angles are outer angles

Option d . ∠2 and ∠6

According to the definition of alternate evterior angles . ∠2 and ∠6 are alternate exterior angles

Hence Option d is pair of alternate exterior angles.

4 0

3 years ago

Hello, please be honest, is this correct?

olga nikolaevna [1]

Yup your right ( i’m just writing here so it lets me send it)

3 0

3 years ago

Read 2 more answers