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Ugo [173]
3 years ago
8

Hello, please be honest, is this correct?

Mathematics
2 answers:
frosja888 [35]3 years ago
6 0

Answer:

Yes that is correct you got keep up good work

olga nikolaevna [1]3 years ago
3 0
Yup your right ( i’m just writing here so it lets me send it)
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Which number is the best approximation for 52√+23√ ?
Agata [3.3K]
<span>52√+23√ = 4.79

Approx 5.1 is the answer.

Hope that helps. -UF aka Nadia
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3 years ago
How many times larger than<br> (15 + 10) is 8 x (15 + 10)?
zvonat [6]

Answer:

8 times larger

Step-by-step explanation:

(15+10) is the singular equation alone. Muiltiply it by 8, and it's 8 times larger then the initial singular expression. Therefore, the answer is 8 times larger.

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3 years ago
Which of the following results in the expressions 0.43 times 52 ?
Mariulka [41]
The answer is 43% of 52. So D
5 0
3 years ago
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PLS HELP DUE SOON GIVING BRAINLIEST
kupik [55]
102 and 102

72 and 72

142 and 142
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3 years ago
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(cot^2x - 1)/(csc^2x) = cos2x​
Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

cos(2x)=cos^2x-sin^2x,

cos(2x)=1-2sin^2x, and

cos(2x)=2cos^2x-1

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants.  Rewriting gives you:

\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}

And canceling out the sin^2 x leaves us with just

cos^2x-sin^2x which is one of our identities.

5 0
3 years ago
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